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A regular CD has a diameter of about 4.75 inches, which means it has a radius of about 2.375 inches. The area of a circle is calculated using the formula A = πr^2, so the area of a regular CD is approximately 17.67 square inches. So, there you have it, the sassy answer to your CD area question.
Standard CDs have a diameter of 120 mm; that would be a radius of 60 mm. Since area is calculated as the value of pi (3.1416) times the square of the radius, we calculate as follows: Area A = pi X r2 = 3.1416 X 60 mm X 60 mm = 3.1416 X 3600 mm2 = 11,309.76 mm2. That value translates to 113.0976 square centimeters or 17.5301631 square inches. The area just calculated includes the hole. If you wish the hole excluded, so you have just the surface area of the disk, subtract the area of the hole, which has a diameter of 15 mm. The hole, with a radius of 7.5 mm, has an area of 176.715 mm2. Subtracting that from the area of a circle with a 120 mm diameter (11,309.76 mm2), we get a true surface area of 11,133.045 mm2 or 17.2562543 in2.
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What is the area of a regular hexagon with side lengths of 12 cm?
what is the area of a regular hexagon with sides lengths of 12 inches long
If a regular octahedron has a surface area of 32 square inches what is the surface area of each face?
32 divided by 8 is 4 inches
If a regular octahedron has a surface area of 48 square inches what is the surface area of each face?
6
What is the area of a regular octagon with a side length of 4 inches and an apothem length of 4.8 inches?
By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base. This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem: Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²
What is the area of a regular heptagon with a side length of 8 in. and an apothem of 8.3 in.?
232.57 square inches.
What is the area of a regular hexagon if the perimeter is 42 inches?
The area is about 127.3 square inches.
What is the area of a regular hexagon inscribed in a circle with a radius of 12 inches?
It is 374.12 sq inches.
What is the area of a regular hexagon with side lengths of 12 cm?
what is the area of a regular hexagon with sides lengths of 12 inches long
What is the area of a regular hexagon with 24 inch perimeter?
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
If s 8 inches and a find the area of the regular hexagon. Round the answer to one decimal place?
The area is 166.3 square inches.
If a regular octahedron has a surface area of 32 square inches what is the surface area of each face?
32 divided by 8 is 4 inches
If a regular octahedron has a surface area of 48 square inches what is the surface area of each face?
6
What is the area of this regular pentagon if the base is 6 inches to the nearest tenth of a square inch?
It is 61.9 square inches.
What is the area of a regular triangle with side length of 15.5 inches?
A triangle with side a: 15.5, side b: 15.5, and side c: 15.5 inches has an area of 104.03 square inches.
What is the area of a regular nonagon with a radius of 14in?
Approx 566.9 square inches.
What is the area forumla for a kite?
For a regular diamond shaped kite, the area would be one half the product of the length of the two sticks. So if it was 20 inches and 30 inches the area would be 300 inches square.
If a regular octahedron has a surface of 32 square inches what is the surface area of each face?
A regular octahedron has 8 faces. If the total surface area is 32 square inches then each face have a surface area equal to one eighth of this. 32/8 = 4 so the surface area of each face is 4 square inches
