Standard CDs have a diameter of 120 mm; that would be a radius of 60 mm. Since area is calculated as the value of pi (3.1416) times the square of the radius, we calculate as follows: Area A = pi X r2 = 3.1416 X 60 mm X 60 mm = 3.1416 X 3600 mm2 = 11,309.76 mm2. That value translates to 113.0976 square centimeters or 17.5301631 square inches. The area just calculated includes the hole. If you wish the hole excluded, so you have just the surface area of the disk, subtract the area of the hole, which has a diameter of 15 mm. The hole, with a radius of 7.5 mm, has an area of 176.715 mm2. Subtracting that from the area of a circle with a 120 mm diameter (11,309.76 mm2), we get a true surface area of 11,133.045 mm2 or 17.2562543 in2.
what is the area of a regular hexagon with sides lengths of 12 inches long
32 divided by 8 is 4 inches
6
By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base. This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem: Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²
232.57 square inches.
The area is about 127.3 square inches.
It is 374.12 sq inches.
what is the area of a regular hexagon with sides lengths of 12 inches long
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
The area is 166.3 square inches.
32 divided by 8 is 4 inches
6
It is 61.9 square inches.
A triangle with side a: 15.5, side b: 15.5, and side c: 15.5 inches has an area of 104.03 square inches.
Approx 566.9 square inches.
For a regular diamond shaped kite, the area would be one half the product of the length of the two sticks. So if it was 20 inches and 30 inches the area would be 300 inches square.
A regular octahedron has 8 faces. If the total surface area is 32 square inches then each face have a surface area equal to one eighth of this. 32/8 = 4 so the surface area of each face is 4 square inches