A regular CD has a diameter of about 4.75 inches, which means it has a radius of about 2.375 inches. The area of a circle is calculated using the formula A = πr^2, so the area of a regular CD is approximately 17.67 square inches. So, there you have it, the sassy answer to your CD area question.
what is the area of a regular hexagon with sides lengths of 12 inches long
32 divided by 8 is 4 inches
6
By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base. This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem: Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²
232.57 square inches.
The area is about 127.3 square inches.
It is 374.12 sq inches.
The area is 166.3 square inches.
The area of a regular hexagon with a 24-inch perimeter is about 41.57 square inches.
what is the area of a regular hexagon with sides lengths of 12 inches long
32 divided by 8 is 4 inches
It is 61.9 square inches.
6
A triangle with side a: 15.5, side b: 15.5, and side c: 15.5 inches has an area of 104.03 square inches.
Approx 566.9 square inches.
For a regular diamond shaped kite, the area would be one half the product of the length of the two sticks. So if it was 20 inches and 30 inches the area would be 300 inches square.
A regular octahedron has 8 faces. If the total surface area is 32 square inches then each face have a surface area equal to one eighth of this. 32/8 = 4 so the surface area of each face is 4 square inches