A regular CD has a diameter of about 4.75 inches, which means it has a radius of about 2.375 inches. The area of a circle is calculated using the formula A = πr^2, so the area of a regular CD is approximately 17.67 square inches. So, there you have it, the sassy answer to your CD area question.
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Standard CDs have a diameter of 120 mm; that would be a radius of 60 mm. Since area is calculated as the value of pi (3.1416) times the square of the radius, we calculate as follows: Area A = pi X r2 = 3.1416 X 60 mm X 60 mm = 3.1416 X 3600 mm2 = 11,309.76 mm2. That value translates to 113.0976 square centimeters or 17.5301631 square inches. The area just calculated includes the hole. If you wish the hole excluded, so you have just the surface area of the disk, subtract the area of the hole, which has a diameter of 15 mm. The hole, with a radius of 7.5 mm, has an area of 176.715 mm2. Subtracting that from the area of a circle with a 120 mm diameter (11,309.76 mm2), we get a true surface area of 11,133.045 mm2 or 17.2562543 in2.
what is the area of a regular hexagon with sides lengths of 12 inches long
32 divided by 8 is 4 inches
6
By joining all the vertices to the centre of the octagon, the apothem forms the height of the triangles with the side of the regular octagon as the base. This the area is 8 × area_triangles = 8 × ½ × side × apothem = 4 × side × apothem: Area_regular_octagon = 4 × side_length × apothem ≈ 4 × 4 in × 4.8 in = 76.8 in²
232.57 square inches.