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Let D represent the length of the diagonal and A the area.
Suppose the sides are L and B.
Then A = L*B
and by Pythagoras, D2 = L2 + B2
These two equations need to be solved as simultaneous equations to get the values of L and B.
One way is to use the following identities:
(L + B)2 = L2 + 2LB + B2 = D2 + 2A so that L + B = sqrt(D2 + 2A)
and
(L - B)2 = L2 - 2LB + B2 = D2 - 2A so that L - B = sqrt(D2 - 2A)
which then give
2L = sqrt(D2 + 2A) + sqrt(D2 - 2A)
and
2B = sqrt(D2 + 2A) - sqrt(D2 - 2A)
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What is the breadth of the rectangle when the area and length is given?
Divide the area by the length of the rectangle
The width of a rectangle is 10 meters and its area is 120 square meters What is the length of the diagonal?
The diagonal is 15.620 meters.
How do you find the area of a rectangle with the diagonal of 13 and a width of 5?
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
What is the perimeter of a rectangle with a diagonal length of 7 feet and an area of 16 feet squared?
The perimeter is 18 feet.
The length and width of a rectangle are 8 inches and 4 inches respectively What would be the area of one of the triangles formed from drawing a diagonal in the rectangle?
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
How do you find the length of rectangle diagonally by using the area given?
You can't. Suppose for instance your rectangle is 1xA, then the diagonal length is sqrt(1+A**2). But if your rectangle is sqrt(A)xsqrt(A) then your diagonal length is sqrt(2*A). The only thing one can say for sure is that the diagonal length is at least sqrt(2*A).
Can you find the area of a rectangle if the problem doesn't show you the base and height?
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.
If the diagonal and the area of a rectangle are 25 m and 168 m2 what is the length of the rectangle?
If the diagonal is 25m and the area is 168m2 then the longest edge of the rectangle will be 24m.
What is the breadth of the rectangle when the area and length is given?
Divide the area by the length of the rectangle
How do you find the area of a rectangle given the length and diagonal?
The area of a rectangle is length times width. If you have the length and a diagonal, you will first have to figure out the width, using the formula of Pythagoras. length2 + width2 = diagonal2; solving for width: width = square root of (diagonal2 - length2). Once you have the width, just multiply lenght x width.
How can you find the area of a rectangle if the given is the perimeter and the diagonal?
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
The width of a rectangle is 10 meters and its area is 120 square meters What is the length of the diagonal?
The diagonal is 15.620 meters.
How do you find the width and length of a rectangle if you only know the diagnol?
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
How do you find the area of a rectangle with the diagonal of 13 and a width of 5?
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
What is the equation for finding length of rectangle?
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
How do you find the area of a rectangle if you only know the width and the diagonal?
Suppose the width is W and the diagonal is D.Then, by Pythagoras's theorem, the length, L, is given by L = sqrt(D^2 - W^2).And then, area = L*W.
How do you find the length of a rectangle given the width and area?
the area of a rectangle = length x widthwe can rearrange this to give uslength of a rectangle = area/ width
