0
Let D represent the length of the diagonal and A the area.
Suppose the sides are L and B.
Then A = L*B
and by Pythagoras, D2 = L2 + B2
These two equations need to be solved as simultaneous equations to get the values of L and B.
One way is to use the following identities:
(L + B)2 = L2 + 2LB + B2 = D2 + 2A so that L + B = sqrt(D2 + 2A)
and
(L - B)2 = L2 - 2LB + B2 = D2 - 2A so that L - B = sqrt(D2 - 2A)
which then give
2L = sqrt(D2 + 2A) + sqrt(D2 - 2A)
and
2B = sqrt(D2 + 2A) - sqrt(D2 - 2A)
Still curious? Ask our experts.
Chat with our AI personalities
Taiga
Vivi
BeauAdd your answer:
Earn +20 pts
What is the breadth of the rectangle when the area and length is given?
Divide the area by the length of the rectangle
The width of a rectangle is 10 meters and its area is 120 square meters What is the length of the diagonal?
The diagonal is 15.620 meters.
How do you find the area of a rectangle with the diagonal of 13 and a width of 5?
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
What is the perimeter of a rectangle with a diagonal length of 7 feet and an area of 16 feet squared?
The perimeter is 18 feet.
The length and width of a rectangle are 8 inches and 4 inches respectively What would be the area of one of the triangles formed from drawing a diagonal in the rectangle?
A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
