Suppose a truck and a car are both running at 40 km/hr.Which
vehicle needs a greater force to stop and why?
88.514Km/hr or 24.587m/s
Speed = distance/time so it is 450/5 = 90 km per hour.
In 1 hour it travels 60 km Hence In 6 hours it travels 6 x 60 = 360 km
60km. 80*.75 = 60.00
a bus travels 300 miles in 6 hours
Dividing distance travelled by time taken gives 450/5 = 90 kilometres per hour.
The average speed of the bus is 40 km/h (20 km / 0.5 hours).
40km/hr
The bus' average speed is 34.72 meters per second.
88.514Km/hr or 24.587m/s
The average speed of the bus is 4.5 miles per hour. This is calculated by dividing the total distance traveled (9 miles) by the total time taken (2 hours).
Speed = distance/time so it is 450/5 = 90 km per hour.
Speed = Distance / Time First bus speed = 300 / 7.5 = 40km/h Second bus speed = 450 / 9 = 50km/h So now we can put them in to a ratio as 40:50. This can be simplified by dividing both by 10 so you have 4:5
The average speed of the bus would be 90 km/h (450 km divided by 5 hours).
The average speed for both men (together) is 6.66... (repeating) km per hour.
To get average speed, divide distance travelled by the time. The answer will be in meters/second. If you want to have your result in km/hour, multiply the number of meters/second by 3.6.
In general, we will find the average speed of a moving object by dividing the total distance it travels by the total time elapsed in its travel.We can find the actual speed of the object if it moves with a constant speed during all of its travel. But if the object is something like a bus or train that makes stops along the way, we discover its average speed by dividing the total distance it travels by the total time it took to travel that distance.