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I assume that you mean 140m Fencing material.
The answer is 1225m(squared), the shape that will hold the most area is a square with sides 35m.




This was calculated using the two equations.
Area=xy
2x+2y=perimeter=140


From 2x+2y=140, y=70 - x


Therefore by substituting y=70-x into the area equation. area = x(70-x)


Differentiate area to equal -2x-70


Stationary Point at 0 so -2x-70=0
Therefore x =35
y=35
Area = 1225


[source : IB Maths]

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Q: What is the biggest area of a rectangular lot that can be enclosed by a hundred forty meters fencing materials?
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