0
What is the center of the circle that has endpoints are 2 7 and -6 -1?
Wiki User
∙ 9y ago
A circle cannot have end points!
Wiki User
∙ 9y ago
Add your answer:
Earn +20 pts
What is the equation of a circle whose endpoints of its diameter are at 2 2 and 10 -4 on the Cartesian plane showing work?
Endpoints: (2, 2) and (10, -4) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to (2, 2) or (10, -4) = 5 which is the radius of the circle Therefore equation of the circle: (x-6)^2 + (y+1)^2 = 25
What is the center of the circle with the endpoints of the diameter at -2 8 and 6 4?
centre is the midpoint of the line → centre = ((-2 + 6)/2, (8 + 4)/2) = (2, 6)
What is the equation of a circle whose diameter endpoints are at 10 -4 and 2 2 on the Cartesian plane and what are the perpendicular equations to its endpoints showing work?
Endpoints of diameter: (10, -4) and (2, 2)Midpoint which is the center of the circle: (6, -1)Distance from (10, -4) or (2, 2) to (6, -1) = 5 which is the radius of the circleEquation of the circle: (x-6)^2 +(y+1)^2 = 25Slope of radius: -3/4Slope of perpendicular equations which will be parallel: 4/31st perpendicular equation: y--4 = 4/3(x-10) => 3y = 4x-522nd perpendicular equation: y-2 = 4/3(x-2) => 3y = 4x-2
Two of the endpoints of the diameter of a circle are at A -6 and 8 and B 6 and -8 1. determine the radius of the circle 2. state an equation of the circle I appreciate the help.?
dinosaurs
What is the equation of a circle having a diameter with endpoints -3 1 and 5 7?
The equation works out as: (x-1)2+(y-4)2 = 25 whereas (1, 4) is the circle's centre and 25 is the radius2
What is the center of the circle with a diameter whose endpoints are (27) and (-6-1)?
Diameter endpoints: (2, 7) and (-6, -1) Centre of circle will be the midpoint which is: (-2, 3)
What are the coordinates of the center of a circle whose diameter has the endpoints (1 4) and (-3 -3)?
Its center is at (-1, 1/2)
A diameter of a circle has endpoints P(-10-2) and Q(46) a.)find the center of the circle b.)find the radius. if your answer is not an integer express it in radical form c.)write an eqaution for the ci?
Endpoints of diameter: (-10, -2) and (4, 6)Midpoint which is the center of the circle: (-3, 2)Radius of the circle: square root of 65Equation of the circle: (x+3)^2 +(y-2)^2 = 65
What is the center of the circle that has a diameter whose endpoints are 1 3 and -7 -1?
Diameter is the square root of (1--7)2+(3--1)2 = 4 times sq rt of 5 Circles center coordinates: (-3, 1)
What is the equation of a circle when the endpoints of its diameter are at 10 -4 and 2 2 on the Cartesian plane?
Endpoints: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to (10, -4) or (2, 2): 5 which is the radius of the circle Therefore equation of the circle: (x-6)^2 + (y+1)^2 = 25
What is the equation of a circle whose endpoints of its diameter are at 2 2 and 10 -4 on the Cartesian plane showing work?
Endpoints: (2, 2) and (10, -4) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to (2, 2) or (10, -4) = 5 which is the radius of the circle Therefore equation of the circle: (x-6)^2 + (y+1)^2 = 25
Does diameter has 2 endpoints that are on the circle?
Yes, it have.
How do you find the center of the circle given the endpoints of the diameter in coordinate geometry?
First, find the coordinates of the diameter midpoint. For example, the endpoints of a diameter have coordinates of (x1, y1) = (1, 2) and (x2, y2) = (7, 6). By the midpoint formula we have: (xm, ym) = [(x2 - x1)/2, (y2 - y1)/2] = [(7 - 1)/2, (6 - 2)/2] = (3, 2) Since (x1, y1) it is the closest point to the origin, the coordinates of the center of the circle are: (xc, yc) = (xm + x1, ym + y1) = (3 + 1, 2 + 2) = (4, 4).
The endpoints of a diameter are given Identify an equation of the circle?
1. Find the coordinates of the center of the circle. Call it point (a, b). To find this point, calculate the average of the x-coordinates of the endpoints, and also the average of the y-coordinates. 2. Find the radius of the circle. Use the formula for distance (which is based on Pythagoras' Theorem). Call the length of the radius "r". 3. The formula for the circle is (x - a)2 + (y - b)2 = r2. Replace the values you found earlier.
What is the center of the circle with the endpoints of the diameter at -2 8 and 6 4?
centre is the midpoint of the line → centre = ((-2 + 6)/2, (8 + 4)/2) = (2, 6)
What is the equation of a circle whose diameter endpoints are at 10 -4 and 2 2 on the Cartesian plane and what are the perpendicular equations to its endpoints showing work?
Endpoints of diameter: (10, -4) and (2, 2)Midpoint which is the center of the circle: (6, -1)Distance from (10, -4) or (2, 2) to (6, -1) = 5 which is the radius of the circleEquation of the circle: (x-6)^2 +(y+1)^2 = 25Slope of radius: -3/4Slope of perpendicular equations which will be parallel: 4/31st perpendicular equation: y--4 = 4/3(x-10) => 3y = 4x-522nd perpendicular equation: y-2 = 4/3(x-2) => 3y = 4x-2
Two of the endpoints of the diameter of a circle are at A -6 and 8 and B 6 and -8 1. determine the radius of the circle 2. state an equation of the circle I appreciate the help.?
dinosaurs
