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A parabola with vertex (h, k) has equation of the form:

y = a(x - h)² + k

→ vertex (k, h) = (2, -1), and a point on it is (5, 0)

→ 0 = a(5 - 2)² + -1

→ 0 = a(3)² -1

→ 1 = 9a

→ a = 1/9

→ The coefficient of the x² term is 1/9

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Q: What is the coefficient of the squared term in the parabola's equation when the vertex is at 2 -1 and the point 5 0 is on it?
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