0
Add your answer:
Earn +20 pts
What is the conjugate of -2 plus 3i?
-2 - 3i
What is conjugate of 2 plus 3i?
- 2 - 3i
8 plus 6i-2 plus 3i?
(8+6i)-(2+3i)=6+3i 8+6i-2+3i=6+9i
Find the sum of negative 2 plus 3i and negative1 minus 2i?
(-2 + 3i) + (-1 - 2i) = -2 + 3i - 1 - 2i = -2 - 1 + 3i - 2i = -3 + i
Which is a conjugate acid base pair in the following equation HS- plus H2O equals S-2 plus H30?
This is a Bronsted question. Hs- is the acid in this which makes H2O a base. Therefore S-2 is the conjugate base and the H3O+ hydronium ion is the conjugate acid.
What is the complex conjugate of 2-3i?
The complex conjugate of 2-3i is 2+3i.
What is the conjugate of -2 plus 3i?
-2 - 3i
What is conjugate of 2 plus 3i?
- 2 - 3i
What is conjugate of 2 3i 2-5i?
The conjugate of 2 + 3i is 2 - 3i, and the conjugate of 2 - 5i is 2 + 5i.
What is the additive inverse and the conjunction of NEGATIVE 2 plus 3i?
-2 + 3iThe additive inverse: -(-2 + 3i) = 2 - 3iThe conjugate: -2 - 3i
What is conjugate of 4i open bracket -2 -3i close bracket?
4i(-2 -3i) = 4i×-2 - 4i×-3i = -8i -12i² = -8i + 12 = 12 -8i → the conjugate is 12 + 8i
8 plus 6i-2 plus 3i?
(8+6i)-(2+3i)=6+3i 8+6i-2+3i=6+9i
What is the product of the complex number a plus bi and its conjugate?
The product is a^2 + b^2.
Which polynomial has rational coefficients a leading leading coefficient of 1 and the zeros at 2-3i and 4?
There cannot be such a polynomial. If a polynomial has rational coefficients, then any complex roots must come in conjugate pairs. In this case the conjugate for 2-3i is not a root. Consequently, either (a) the function is not a polynomial, or (b) it does not have rational coefficients, or (c) 2 - 3i is not a root (nor any other complex number), or (d) there are other roots that have not been mentioned. In the last case, the polynomial could have any number of additional (unlisted) roots and is therefore indeterminate.
Find the sum of negative 2 plus 3i and negative1 minus 2i?
(-2 + 3i) + (-1 - 2i) = -2 + 3i - 1 - 2i = -2 - 1 + 3i - 2i = -3 + i
What is the cartesian form of this complex no 1 plus i cube?
(1+i)3 = 1 + 3i - 3 - i = -2 + 2i This is a complex number, and therefore cannot be plotted on a Cartesian plane.
How do you solve complex fraction?
this is a very good question. lets solve (2+3i)/(4-2i). we want to make 4-2i real by multiplying it by the conjugate, or 4+2i (4-2i)(4+2i)=16-8i+8i+4=20, now we have (2+3i)/20 0r 1/10 + 3i/20 notice that -2i times 2i = -4i^2 =-4 times -1 = 4
