the derivative of tangent dy/dx [ tan(u) ]= [sec^(2)u]u' this means that the derivative of tangent of u is secant squared u times the derivative of u.
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Yes, the derivative of an equation is the slope of a line tangent to the graph.
Take the derivative of the function.
-ln|cos x| + C
d/dx[ tan-1(x) ] = 1/(1 + x2)
Tangent = 0.5