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24 feet?
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∙ 13y ago
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How long should each side be for a octagon 10 feet in diameter?
Approx 3.83 feet.
How long is each side of a 5 inch diameter octagon?
The length of a single edge of an octagon can be calculated by measuring the diameter, then dividing this length by the square root of the sum of four and two times the square root of two, which would be written in a calculator as sqrt(4+(2*sqrt(2))). In this case, a five inch diameter equates to approximately 1.913 inches per side.
How many square feet in a 8 foot octagon?
There is nothing in the question to indicate that it is a regular octagon and since that cannot be assumed, there is not enough information to calculate its area. Even if it were regular, the answer will depend what the 8-foot measure refers to: the length of a side of the octagon, its diameter, its apothem etc.
If an octagon has a circumference of 24 what is its diameter?
I assume that when you say "circumference", you really mean "perimeter" of the octagon. I also assume that by saying, "diameter", you really refer to the widest distance between two points on the octagon. An octagon has 8 sides, so if you divide 24 by 8, then you have 3 units of length per side. Then if you were to draw lines from the center of the octagon out to the ends of the segments of the perimeter, then those lines would be 45 degrees apart from each other. In order to find the "diameter", you need to find the length of one of those lines drawn from the center of the octagon, then double it. To do this, you need to perform some trigonometry. To perform the trig, the easiest thing would be to use a right triangle. By drawing a line from the center of the octagon, perpendicular (at a right angle) to one of the outside segments of the octagon, you bisect the 45 degree angle created by the two lines on either side of it. So then you have created a right triangle inside of the octagon, with a 1.5 unit long side, and an opposing 22.5 degree angle. In this case, you want to find out the length of the longest side of this triangle, which is the hypotenuse. So, the sine of the angle 22.5 degrees is equal to 1.5 units divided by the length of the hypotenuse. If you solve for the hypotenuse, you get 3.92 units, rounded. Double this gives you 7.84 units across the octagon.
Can you call any 8 side shape an octagon?
No not just any shape that has 8 side can be called an octagon. An octagon has straight lines that make up a closed bounded shape.
what is diameter of octagon when each side is 34 inches?
Diameter = 88.84 inches
What is octagon side length?
The side length is the diameter multiplied by tan22.5. S=Dtan22.5
What is the diameter of an octogon when each side is 18 inches in length?
An octagon is a polygon with 8 sides. To find the diameter of a regular octagon when each side is 18 inches in length, you can use the formula: Diameter = Side length × √(2 + √2) Plugging in the given side length (18 inches): Diameter = 18 × √(2 + √2) ≈ 56.97 inches So, the diameter of the octagon is approximately 56.97 inches.
What is the length of each side of an octagon that is 48 inches in diameter?
Since the diameter is 48 inches, and there are 8 sides, then each side will be 48/8 = 6 inches.
How long should each side be for a octagon 10 feet in diameter?
Approx 3.83 feet.
How long should each side for a octagon 10 feet in diameter?
4.14 feet, approx.
What is the formula for an octagon?
There is no formula for an octagon. There are formulas for figuring out different aspects of an octagon, such as its perimeter, diameter, etc.
What is the side length of an 8 inch diameter octagon?
The side length is 2/[cos(pi/4)*cos(pi/8)] = 3.06 inches, approx.
How long is each side of a 5 inch diameter octagon?
The length of a single edge of an octagon can be calculated by measuring the diameter, then dividing this length by the square root of the sum of four and two times the square root of two, which would be written in a calculator as sqrt(4+(2*sqrt(2))). In this case, a five inch diameter equates to approximately 1.913 inches per side.
What is the area of a 12feet diameter to the nearest foot?
Divide the diameter by the value of Pi and you'll have your answer. Hint: it's more than 3.5 but less than 4.0 !
What is the diameter of an octagon with 12 inch sides?
It could be any value in the range (0, 48) inches, depending on how eccentric the octagon was and which of its diameters was measured. For a regular octagon, the diameter is 31.4 inches (approx).
How do you find the perimeter of an octagon if you know the diameter?
I presume by diameter of an octagon you mean the length of the diagonal between opposite vertices of a regular octagon. By completing all the diagonals between opposite vertices of a regular octagon, it divides it up into 8 equal isosceles triangles, with their apexes at the centre of the octagon. The two sides of these isosceles triangles which go from a vertex of the octagon to the centre has a length half that of the diameter. If the centre point of each side of the octagon is joined to the centre of the octagon, each of the 8 isosceles triangles above are split into two (congruent) right angled triangles. The angle at the centre of the octagon of each of these triangles is (360° ÷ 8) ÷ 2 = 22.5°. The side opposite this angle is half the length of the side of the octagon and so the perimeter is 16 times its length. The hypotenuse of the right angled triangles is half the diameter. Thus the trigonometric sine function can be used to find half the octagons side length, and thus its perimeter: sin = opp/hyp → opp = sin x hyp Perimeter = 16 x opp = 16 x (sin 22.5° x diameter/2) = diameter x 8 x sin 22.5° ≈ diameter x 3.061 This can be generalised to any regular even sided polygon if diameter is defined as the length of the diagonal between opposite vertices (which is also the maximum straight line distance between two points on the perimeter): perimeter = diameter x number_of_sides x sin(180° ÷ number_of_sides) As the number of sides increases, "number_of_sides x sin(180° ÷ number_of_sides)" gets closer and closer to π.
