The discriminant is 25.
Presumably you mean: -2x2-3x+41 If so then the discriminant is: (-3)2-4*-2*41 = 337 The expession is: i/2+i
I'm going to assume the polynomial in question is 2x7+(3-2x3)+(5x8-4x) Expanding out the polynomial: 2x7+3-2x3+5x8-4x Order the terms by powers of x: 5x8+2x7-2x3-4x+3 Since 8 is the highest power of x, the degree of the polynomial is 8.
The discriminant says; b^2 - 4ac 1^2 - 4(2)(7) = 1 - 56 < 1 So, less than 1 and no real roots
The discriminant is b2 - 4ac. In this case, a = 1, b = 7, and c = 2. Just replace and calculate.
The discriminant is 88.
The discriminant is 25.
The discriminant is -199.
The discriminant is 88.
The discriminant is 1.
-7
65
88 -Apex ;)
-7 therefore the quadratic equation has no real roots
2x2 + 10x - 3 The discriminant is defined as b2 - 4ac, so for this function b=10, a=2, and c=-3 So the discriminant is 100-4*2*-3 = 124
The discriminant is 88 which means that the given quadratic equation has two different solutions for x
The discriminant is -7