The discriminant is -7
-7
-7 therefore the quadratic equation has no real roots
2X2+5x-12 4+5x-12 -8+5x 5x-8
A quadratic polynomial.
b2 - 4ac (whatever that 4's sign is it is positive when squared ) (4)2 - 4(2)(- 9) 16 + 72 = 88 ===============Two real roots.
-7
Discriminant = 52 - 4 x 2 x (-8) = 89
-7 therefore the quadratic equation has no real roots
52-4*7*1 = -3 The discriminant is less than zero so the quadratic equation will have no solutions.
2x^(2) - 5x - 12 First write down all the factors of '2' & '12' 2 = 1,2 12 = 1,12; 2,6; 3,4 . From this we select two pairs of numbers, one pair from each coefficient, that add/multiply to '5' They are, 1,2 & 3,4 Hence -(2 x 4) + (1 x 3) = -8 + 3 = -5 Set up the brackets (2x 3)(x 4) Hence the signs are ( 2x + 3)(x - 4)
2X2+5x-12 4+5x-12 -8+5x 5x-8
x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)
A quadratic polynomial.
b2 - 4ac (whatever that 4's sign is it is positive when squared ) (4)2 - 4(2)(- 9) 16 + 72 = 88 ===============Two real roots.
If you mean: 4x squared+7x+4 then the discriminant is -15
Trinomial
2X2 + 3X - 4 = 0the discriminant is,b2 - 4ac32 - 4(2)(- 4)9 + 32 = 4141 > 1this means there are two real roots to this equation