For any x ≠ 0, x2 -10/x2 - 4 +3x/x2 - 4 LCD = x2, multiply each term by their missing element of LCD = (x4 + 10 +3x - 8x2)/x = (x4 - 8x2 + 3x + 10)/x2
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
The discriminant b2-4ac is -23
x2 - 3x + 2 = 0
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
The discriminant of the given quadratic expression is -7
The discriminant is -11.
This quadratic expression can't be factored because its discriminant is less than zero.
The discriminant formula. b2 - 4ac 32 - 4(1)(8) 9 - 32 = - 23 ===========This shows no real roots to this function.
If you mean x2-3x+5 then the answer is none because its discriminant is less than zero
(x2+3x-4) (x-4)
(x2 + 3x + 5)(x2 - 3x + 4)
The discriminant is -27 and so there are no real roots.
No because the discriminant is less than zero.
The discriminant is 9.
x2+3x+8 is a trinomial But this quadratic equation will have no solutions because its discriminant is less than zero.
For any x ≠ 0, x2 -10/x2 - 4 +3x/x2 - 4 LCD = x2, multiply each term by their missing element of LCD = (x4 + 10 +3x - 8x2)/x = (x4 - 8x2 + 3x + 10)/x2