The discriminant of x2+3x+4 is -7 therfore it has no real roots.
For any x ≠ 0, x2 -10/x2 - 4 +3x/x2 - 4 LCD = x2, multiply each term by their missing element of LCD = (x4 + 10 +3x - 8x2)/x = (x4 - 8x2 + 3x + 10)/x2
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
The discriminant b2-4ac is -23
x2 - 3x + 2 = 0
The discriminant in the quadratic equation x2 + 11x + 121 = x + 96 is 0.Simplify the equation to the form Ax2 + Bx + C = 0 and you get x2 + 10x + 25 = 0. The discriminant is B2 - 4AC or 100 - (4)(1)(25) or 100 - 100 or 0.Not asked, but answered for completeness - since the discriminant is 0, there is one real solution, namely x = (-10 +/- 00.5) / 2 = -5
The discriminant of the given quadratic expression is -7
The discriminant is -11.
This quadratic expression can't be factored because its discriminant is less than zero.
The discriminant formula. b2 - 4ac 32 - 4(1)(8) 9 - 32 = - 23 ===========This shows no real roots to this function.
If you mean x2-3x+5 then the answer is none because its discriminant is less than zero
(x2+3x-4) (x-4)
(x2 + 3x + 5)(x2 - 3x + 4)
The discriminant is -27 and so there are no real roots.
No because the discriminant is less than zero.
The discriminant is 9.
x2+3x+8 is a trinomial But this quadratic equation will have no solutions because its discriminant is less than zero.
x2 + 3x - 6 = 0 a = 1, b = 3, c = -6 D = b2 - 4ac = 32 - 4(1)(-6) = 9 + 24 = 33 Since D > 0, the equation has two different real solutions.