x = -5 x = 2
if x2 + 7 = 37, then x2 = 29 and x = ±√29
3x3 + 6x2 - 24x = 3x(x2 + 2x - 8) = 3x(x2 + 4x - 2x - 8) = 3x[ x(x + 4) - 2(x + 4) ] = 3x(x - 2)(x + 4)
x2/(3x2 - 5x - 2) - [2x/ (3x + 1)][1/(x - 2)] = x2/(3x2 - 6x + x - 2) - 2x/(3x + 1)(x - 2) = x2/[3x(x - 2) + (x - 2)] - 2x/(3x + 1)(x - 2) = x2/(3x + 1)(x - 2) - 2x/(3x + 1)(x - 2) = (x2 - 2x)/(3x + 1)(x - 2) = x(x - 2)/(3x + 1)(x - 2) = x/(3x + 1)
x^2 + 3x +7 = 0 doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-3 plus or minus the square root of -19) divided by 2x = -1.5 + 2.179449471770337ix = -1.5 - 2.179449471770337iwhere i is the square root of negative 1
The discriminant is -11.
The discriminant is -27 and so there are no real roots.
The discriminant of x2+3x+4 is -7 therfore it has no real roots.
The discriminant of the given quadratic expression is -7
There are no real solutions because the discriminant of the quadratic equation is less than zero.
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
If you mean x2-3x+5 then the answer is none because its discriminant is less than zero
The discriminant is 9.
The discriminant of x^2 + 6 - 16 = discriminant of x^2 - 10 is 40.
No because the discriminant is less than zero.
-2
x2 + 3x + 7 = 5 ∴ x2 + 3x + 2 = 0 ∴ (x + 1)(x + 2) = 0 ∴ x ∈ {-2, -1}