The operator (+ or -) before the 5 (and before the 6, but that doesn't matter for the discriminant) is missing from the question, so:
It is an equation and the value of x is -5
6x - 5 -5 = 0 6x -10 = 0 +10=+10 6x=10 x= about 1.4
If you mean: 6x-5 = 31 then x = 6
6!
6x + 8 = 13, 6x = 13 - 8, 6x = 5, x = 5/6
b^2 - 4ac Is the discriminant. 6^2 - 4(3)(5) 36 - 60 = - 24 < 0 so, an unreal answer and no real X intercepts
-3x2 = 5 + 3x (add 3x2 to both sides)0 = 3x2 + 5 + 3x or3x2 + 3x + 5 = 0 (since the discriminant is less than zero, we have complex roots)x = [-3 ± √[(32 - 4(3)(5)]]/2(3)x = [-3 ± √(9 - 60)]/6x = (-3 ± √-51)/6x = (-3 ± i√51)/6x = (-3 + i√51)/6 = -1/2 + (√51/6)i orx = (-3 - i√51)/6 = -1/2 - (√51/6)i
From what i understand the equation is like this; (3 * 2 ) + 6x + 24 = 0 6 + 6x +24 = 0 6x = - 24 - 6 6x = - 30 x = - 5
That depends on what you mean by "6x 5", which could be 6x * 5, 6x + 5, 6x - 5, 6x / 5, 6x5, etc.
You can find the x-coordinate of it's vertex by taking it's derivative and solving for zero: y = -3x2 + 12x - 5 y' = -6x + 12 0 = -6x + 12 6x = 12 x = 2 Now that we have it's x coordinate, we can plug it back into the original equation to find it's y coordinate: y = -3x2 + 12x - 5 y = -3(2)2 + 12(2) + 5 y = -12 + 24 + 5 y = 17 So the vertex of the parabola y = -3x2 + 12x - 5 occurs at the point (2, 17).
3x2-9x-30 =3x2+6x-15x-30 =3x(x+2)-15(x+2) =(3x-15)(x+2) OR 3(x - 5)(x+2)
-6x - 5 + 10It's an algebraic expression in 'x'. It can be simplifiedby combining like terms:-6x + 5Its numerical value depends on the value of 'x'.
The browser that is used for submitting questions does not permit many mathematical symbols. It is therefore not possible to be sure what the question was. For a quadratic equation of the form y = ax^2 + bx + c, where a, b and c are real numbers and a is non-zero, the discriminant is b^2 – 4ac.
f(x) = 3x2 + 5x + 2fprime(x) = 6x + 5
It too will have a value of 5
6x - 1 = 29 => 6x = 30 => x = 5 Then x2 + x = 25 + 5 = 30
The value of X in the equation 2x-1-6 5 plus 6x is -3.