(x^2)^(1/2) equals x, therefore, y = x+4, which has a range and domain of all real numbers. The graph is a straight line, slope of 1, y-intercept of 4. Are you actually saying y = (x^2+4)^(1/2). If so, the range and domain will also be all real numbers because x^2+4 will never result in a negative number.
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
y is greater than 0 x exist in a set of real numbers
What is the domain and range of absolute lxl - 5
matrix
A square number is a number which is an integer squared:14916253649648110011 squared is 121, which is outside of the desired range.
The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
Domain is greater than or equal to zero. same with range
The answer depends on the domain for x. For example, if the domain is x = 7, then the range is 55. If the domain is all Real numbers, then the range is y >= 6.
The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, ∞).
y is greater than 0 x exist in a set of real numbers
Domian is x>-6 Range is y> or equal to 0
The domain of y = 1/x2 is all numbers from -infinity to + infinity except zero. The range is all positive numbers from zero to +infinity, except +infinity.
domain: (-infinity to infinity) range: ( -infinity to infinity)
The domain would be (...-2,-1,0,1,2...); the range: (12)
domain: all real numbers range: {5}
The Domain and Range are both the set of real numbers.