define eigen value problem
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The answer is yes, and here's why: Remember that for the eigenvalues (k) and eigenvectors (v) of a matrix (M) the following holds: M.v = k*v, where "." denotes matrix multiplication. This operation is only defined if the number of columns in the first matrix is equal to the number of rows in the second, and the resulting matrix/vector will have as many rows as the first matrix, and as many columns as the second matrix. For example, if you have a 3 x 2 matrix and multiply with a 2 x 4 matrix, the result will be a 3 x 4 matrix. Applying this to the eigenvalue problem, where the second matrix is a vector, we see that if the matrix M is m x n and the vector is n x 1, the result will be an m x 1 vector. Clearly, this can never be a scalar multiple of the original vector.
The answer to a division problem is called a quotient or divide. The answer to a division problem is called a quotient or divide.
The sum is the answer in an addition problem.
A hypothetical problem is a problem that has not yet actually happened. Usually hypothetical problems are discussed in order to prepare for the problem, should it occur.
The answer in a subtraction problem is difference.
Gillian Frances Colkin has written: 'The location of roots of equations with particular reference to the generalized eigenvalue problem'
To find the largest eigenvalue of a matrix, you can use methods like the power iteration method or the QR algorithm. These methods involve repeatedly multiplying the matrix by a vector and normalizing the result until it converges to the largest eigenvalue.
The maximum eigenvalue is important in determining the stability of a system because it indicates how quickly the system will reach equilibrium. If the maximum eigenvalue is less than 1, the system is stable and will converge to a steady state. If the maximum eigenvalue is greater than 1, the system is unstable and may exhibit oscillations or diverge over time.
No.
Yes, it is.
No. Say your matrix is called A, then a number e is an eigenvalue of A exactly when A-eI is singular, where I is the identity matrix of the same dimensions as A. A-eI is singular exactly when (A-eI)T is singular, but (A-eI)T=AT-(eI)T =AT-eI. Therefore we can conclude that e is an eigenvalue of A exactly when it is an eigenvalue of AT.
Anurag Gupta has written: 'Krylov sub-space methods for K-eigenvalue problem in 3-D multigroup neutron transport' -- subject(s): Neutron transport theory
Ricardo Macias Carrasco has written: 'The eigenvalue problem in the OL/2 language' -- subject(s): Data processing, Eigenvalues, OL/2 (Computer program language)
how does ahp use eigen values and eigen vectors
If a linear transformation acts on a vector and the result is only a change in the vector's magnitude, not direction, that vector is called an eigenvector of that particular linear transformation, and the magnitude that the vector is changed by is called an eigenvalue of that eigenvector.Formulaically, this statement is expressed as Av=kv, where A is the linear transformation, vis the eigenvector, and k is the eigenvalue. Keep in mind that A is usually a matrix and k is a scalar multiple that must exist in the field of which is over the vector space in question.
Yes it is. In fact, every singular operator (read singular matrix) has 0 as an eigenvalue (the converse is also true). To see this, just note that, by definition, for any singular operator A, there exists a nonzero vector x such that Ax = 0. Since 0 = 0x we have Ax = 0x, i.e. 0 is an eigenvalue of A.
The maximal eigenvalue of a matrix is important in matrix analysis because it represents the largest scalar by which an eigenvector is scaled when multiplied by the matrix. This value can provide insights into the stability, convergence, and behavior of the matrix in various mathematical and scientific applications. Additionally, the maximal eigenvalue can impact the overall properties of the matrix, such as its spectral radius, condition number, and stability in numerical computations.