So, the equation will be written in slope-intercept form, which is the easiest for me to write out. Here it is: y=-.6667x+2. The -.6 is repeating. "-.6667" is the slope, "x" a point on the line, and "2" the intercept. The formula for this kind of equation is "y=mx+b." I really hope this helps!
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If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
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The equation of a line written in slope intercept form has the form of y = mx + b. In this form, m is the slope of the line and b is the y intercept.
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When finding the y-intercept, plug in x=0 y = 4x + 2 y = 4(0) + 2 y = 2 So your intercept is (0,2)
If you mean: y = 2x-3 then the slope is 2 and the y intercept is -3
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1) Solve the given equation for "y". The resulting equation will be in slope-intercept form, so you can immediately read off its slope. 2) Any line parallel to that line will have the same slope.
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If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
x-intercept is -3, (-3, 0) y-intercept is -2, (0, -2) The line passes through these two points, (-3, 0) and (0, -2). Then the slope will be: m = (-2 - 0)/[0 - (-3)] = -2/3 Let's use one of the point; (-3, 0) y - y1 = m(x - x1) y - 0 = (-2/3)[x - (-3)] y = (-2/3)x -2 This is the equation of the line. (This is the slope intercept form) Or use the intercept form: x/a + y/b + 1, where a is x-intercept, and b is y-intercept. So, x/-3 + y/-2 = 1 (x/-3)(-6) + (y/2)(-6) = -6 2x + 3y = -6, which is the general form of the equation for the line.
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If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.