The equation of a line with gradient m passing through point (xo, yo) is given by:
y - yo = m(x - xo)
The gradient m is calculated:
m = change_in_y/change_in_x
= y1-y0/x1-x0
→ line through points po (2, 3) and p1 (4, -1) has equation:
y - 3 = (-1 - 3)/(4 - 2) (x - 2)
→ y - 3 = -4/2 (x - 2)
→ y - 3 = -2(x - 2)
→ y - 3 = -2x + 4
→ y + 2x = 7
y=-x
Y=4x+3
y = 2/3x+4 or in the general form of sraight line equation as 2x-3y+12 = 0
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
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The formula for a line is: Y = mX + b
The equation is x = 2
x = 2
The equation of the line passing through the points (mx, ny) and (2, 5) is y ((5-ny)/(2-mx))x (5 - ((5-ny)/(2-mx))2).
Points: 0 2 and 6 0 Equation: y = -1/3x+2
y = -1.125x + 2.25
y = 4
What is the equation of the vertical line passing through (-5,-2)
y = 2.25x -6
If you mean of points of (3, -4) and (5, 1) then the equation works out as 2y=5x-23
Points: (2, 2) and (3, 1) Slope: -1 Equation: y = -x+4
The equation of a vertical line passing through the point (a, b) is x a.