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What else can I help you with?
How do you work out gradients and intercepts?
Gradients can be worked out by: 1. gradient formula, suppose the two points are (x1,y1); (x2,y2) then the gradient=(y2-y1)/(x2-x1) 2. rise/run Intercepts can be found by: 1. to find the x-intercept substitute y=0 into the equation of the line 2. to find the y-intercept substitute x=0 into the equation of the line
What is The equation of a line in slope-intercept form for a line with slope = 2 and y-intercept at (0,3)?
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What is the y intercept and slope of y 3 over 2 x?
There is a missing equals. When the equation of a line is written in the form: y = mx + c m is the gradient/slope of the line; and c is the y intercept. If your line is ``y = 3/2 x'' then y = 3/2 x → y = 3/2 x + 0 → slope is 3/2 & y intercept is 0.
Is the equation of a line in slope-intercept form for a line with slope and y-intercept at (0 -2)?
If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
Write the equation in slope-intercept form of the line that has a slope of 2 and y-intercept of -2.?
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What is the equation of the line with an x-intercept of -1 and a y-intercept of 2?
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What is the gradient of a line with the equation y equals 5x - 2?
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What is -2x plus y equals -4?
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What is the equation of a line perpendicular to 3x-2y7 with a y- intercept of 5?
The gradient of the given line is 2/3. Gradient of the perpendicular is -3/2 The equation, therefore, is y = -(3/2)x + 5 or 2y = -3x + 10 or 3x + 2y - 10 = 0
How do you write an equation of a line?
So glad I'm here... Just had a test on this today! y=mx+c m=gradient (followed by 'x') and c=y-intercept Depending on which way the line is slanting the gradient is either negative or positive. If the y-intercept was something like -2 and the gradient 2, then it would be written like this: y=2x-2.
What is the equation to a line that has a y intercept of 4 and a slope of 2?
Assuming it is a straight line, the equation will be -- y=2x+4 The general equation for a straight line is y=mx+c, where -'m' is the gradient (or slope), and -'c' is the y-intercept. So, if we substitute in your values for m and c, we get y=2x+4
What is the equation in slope intercept form of the line that has a slope of -2 and y intercept of 2?
The equation of a line in slope-intercept form is given by ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope of -2 and a y-intercept of 2, the equation is: [ y = -2x + 2. ]
How do you work out gradients and intercepts?
Gradients can be worked out by: 1. gradient formula, suppose the two points are (x1,y1); (x2,y2) then the gradient=(y2-y1)/(x2-x1) 2. rise/run Intercepts can be found by: 1. to find the x-intercept substitute y=0 into the equation of the line 2. to find the y-intercept substitute x=0 into the equation of the line
What is The equation of a line in slope-intercept form for a line with slope = 2 and y-intercept at (0,3)?
-1
The gradient of the line y2x 1?
If you mean: y = 2x+1 then the gradient is 2 and the y intercept is 1
What is the y intercept and slope of y 3 over 2 x?
There is a missing equals. When the equation of a line is written in the form: y = mx + c m is the gradient/slope of the line; and c is the y intercept. If your line is ``y = 3/2 x'' then y = 3/2 x → y = 3/2 x + 0 → slope is 3/2 & y intercept is 0.
What is the equation of a line with an x-intercept of 4 and a y-intercept of -2?
To find the equation of a line with an x-intercept of 4 and a y-intercept of -2, we can use the intercept form of the equation of a line, which is ( \frac{x}{a} + \frac{y}{b} = 1 ), where ( a ) is the x-intercept and ( b ) is the y-intercept. Substituting the values, we get ( \frac{x}{4} + \frac{y}{-2} = 1 ). Multiplying through by -4 to eliminate the fractions, the equation simplifies to ( 2x + 4y = -8 ) or, rearranging, ( y = -\frac{1}{2}x - 2 ).
