(x - 2)(x + 2)(x - 3)(x + 3)
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x2 + 36 cannot be factored. You can only factor the difference of two squares, not the sum.
(5w-6)2
4 is a factor of 36 and 36 is a multiple of 4
2x + 6 = 2(x + 3) so 2x + 6 = 0 implies x = -3 Now, substitute x = -3 in 8x3 + 20x2 + 36 which is -8*27 + 20*9 + 36 = -216 + 180 + 36 = 0 So -3 is a root of 8x3 + 20x2 + 36 ie, by the remainder theorem, (x + 3) is a factor. Also, each of the coeffivcients in the expression is even, so 2 is also a factor. So 2*(x + 3) or (2x + 6) is a factor.
No. 36 is composite and so it cannot be a prime factor.