x^(2) + 13x + 36
Factors to
( x + 9)(x + 4)
When learning factoring. ;-
#1 ; If the coefficient of x^(2) is '1' , as in this case. Then
#2 ; Write down all the factors of 36, which are ,1,36 ' 2,18 ' 3,12 ' 4,9 ' 6,6 ;
#3 ; Out of these pairs of factors, select a pair that add/subtract to '13'.
#5, They are 4,9 ; 4 + 9 = 13
#6 ; Since the quadratic eq;m has positive (+) signs , then all the signs in the brackets are positive(+).
When the coefficient of x^(2) is > 1, and/or the signs are different , then different techniques come into play.
common factor in -36 and 63
The highest common factor of the numbers 36, 60 and 72 is 12.
12
It is: 36 because 6*6 = 36
the greatest common factor of 18 24 and 36 is 6 GLAD I COULD HELP
(x + 9)(x + 4)
x^(2) - 13x + 36 Factors to ( x - 9)(x - 4)
(x + 4)(x + 9)
To factor the expression (x^2 + 13x + 36), you need to find two numbers that multiply to 36 (the constant term) and add up to 13 (the coefficient of the linear term). The numbers 9 and 4 meet these criteria, as (9 \times 4 = 36) and (9 + 4 = 13). Therefore, you can factor the expression as ((x + 9)(x + 4)).
x2 + 13x + 36 = 0 so (x+4)(x+9) = 0 so that x = -4 or x = -9
x2-13x+36=(x-9)(x-4)=0 x=9 or x=4
(x - 9)(x - 4)
(x -3)(2x2 + 3x - 4)
Well, if that was a - 13X we could factor by inspection, but now the quadratic formula is needed. By inspection the discriminant yields two real roots. X^2 + 13X + 36 = 0 X = - b (+/-) sqrt(b^2-4ac)/2a a = 1 b = 13 c = 36 X = - 13 (+/-) sqrt[b^2 - 4(1)(36)]/2(1) X = - 13 (+/-) sqrt(169 - 144)/2 X = - 13 (+/-) sqrt(25)/2 X = [- 13 (+/-) 5]/2 X = - 4 ------------ X = - 9 -----------
(x+9)(x+4)
x-4 is the correct answer for Apex
n^2(n + 6)(n^2 - 6n + 36)