0
117
39,3
13,3,3
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∙ 10y ago
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What is a factor tree of 117?
13x9= 117 13 is prime so you don't continue with 13 because nothing goes into it equally. Then you continue with 9, and obviously 3 goes into 9 three times. (3x3=9) Now, since nothing goes evenly into three, we stop our factor tree. (:
Is 117 divisible by 5?
No. 5 is not a factor of 117
How do you make a factor tree for 7?
You cannot really make a factor tree for 7 because it is already a prime number.
What is the factor tree of 21?
3x7=21 3 and 7 are prime numbers, so 3x7 is the factor tree of the number 21.
What is the factor tree for 37?
37 is a prime number so it cant be broken into a factor tree. its only factors are 37 and 1
What is the factor tree of117?
117 39,3 13,3,3
What number is multiplied to make 117?
The factor pairs of 117 are: 1 x 117 3 x 39 9 x 13
How do you write a factor tree for a prime number?
The purpose of a factor tree is to notate the process of finding the prime factorization. If a number is already prime, a factor tree is not necessary.
Can 1 and the factor be used itself to be a factor tree?
The purpose of a factor tree is to divide a number into prime factors. 1 is not a prime number.
What is a factor tree for 13?
13 is a prime number so it doesn't have a factor tree.
What is the factor tree for 57?
There is no factor tree nor factors of 57 as it is a prime number.
What is a common factor of 117 and 16?
the common factor of 16 and 117 is : 1
Can the number one sometimes be used as a factor in a factor tree?
no
What is a factor tree for the number 19?
19 is prime. No tree.
What is a factor tree of 117?
13x9= 117 13 is prime so you don't continue with 13 because nothing goes into it equally. Then you continue with 9, and obviously 3 goes into 9 three times. (3x3=9) Now, since nothing goes evenly into three, we stop our factor tree. (:
What is factor tree of a number?
A factor tree of number is (I think) the numbers that multiply together to form a product. They are prime numbers, too.
Does it matter which factor you start with when beginning a factor tree for a composite number?
No.
