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If an expression does not have a common factor, then it is called a "prime" expression.
It's the general form of a quadratic expression and it can be factored providing its discriminant is not less than zero.
This expression can not be factored. It is already in it's simplest state.
6•2+6•3
It can be factored as 18(5-2x^2)
When the expression is broken down into its prime factors it is factored completely.
If an expression does not have a common factor, then it is called a "prime" expression.
It is irreducible, it can't be factored.
k^(2) - 9h^(2) First recognise that '9' = 3^(2) Hence k^(2) - 3^(2)h^(2) => k^(2) - (3h)^(2) (Factor (k - 3h)( k + 3h) Fully factored. NB First if any coefficients are squared numbers. Secondly, two squared terms with a negative(-) between them factors. This does NOT happen if there is a positive(+) between. Lastly the bracketed terms should each have a different sign. NNB The Pythagorean Eq'n ; h^(2) = a^(2) + b^(2) does NOT factor. However, if algebraically rearranged to ; a^(2) = h^(2) - b^(2) factors to a^(2) = (h - b)(h + b)
18 + 8x + x = = 18 + 9x = 9(2 + x) which is the factored form of the expression.
It's the general form of a quadratic expression and it can be factored providing its discriminant is not less than zero.
The expression (5n^2 - 6n) can be factored by taking out the greatest common factor, which is (n). This gives us (n(5n - 6)). Thus, the factored form of the expression is (n(5n - 6)).
The expression ( (24a + 56b) ) can be factored by finding the greatest common factor (GCF) of the coefficients. The GCF of 24 and 56 is 8, so the equivalent expression can be factored as ( 8(3a + 7b) ).
That expression can not be factored.
It is irreducible, it can't be factored.
If you mean (1+2x)2, that is already factored.
This quadratic expression can't be factored because its discriminant is less than zero.