(2x + 1)(x + 2)
(2x-3)(x-1)
The answer is (2x^2+3)(4x+1)
(2x-4)(x-1) = 0
3x(2x + 1)
(x + 1)(2x + 5)
(2x + 1)(x + 2)
x(x + 2)
(x - 1)(2x - 9)
(2x-3)(x-1)
The answer is (2x^2+3)(4x+1)
There is no rational factorisation.
4
(4x + 1)(2x + 3)
(2x-1)(2x-1) = 4x^2 -4x + 1
(2x-4)(x-1) = 0
2(x + 3)(x + 1)