This quadratic expression can't be factored because its discriminant is less than zero.
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x2-18x+81 = (x-9)(x-9) when factored
Divide all terms by 3 and so x2+18x+81= (x+9)(x+9) when factored
To factor this, find two numbers whose product is 81 and sum 18. These two numbers are therefore 9 and 9. So we can rewrite the polynomial in its factored form as follows: (k+9)(k+9), or "k plus 9 squared"
78 + 79 + 80 + 80 + 81 + 81 = 479
2x2+5x+3 = (2x+3)(x+1) when factored