3x2 + 6x - 24
First factor out any common factors of the three terms. In this case, each term is a multiple of 3. So,
3x2 + 6x - 24 = 3(x2 + 2x - 8)
Next, use the reverse FOIL method to factor the polynomial in the parenthesis (x2 + 2x - 8). x2 factors out to x * x:
(x + ??)(x + ??)
Now, we must find two numbers that add to get 2 (from the 2x) and multiply to get -8. Those numbers are -2 and 4. So,
(x2 + 2x - 8) = (x - 2)(x + 4)
So,
3x2 + 6x - 24 = 3(x - 2)(x + 4)
3x2 + 5x + 2 is a quadratic expression that can be factored as follows: 3x2 + 5x + 2 = 3x2 + 3x + 2x + 2 = 3x(x + 1) + 2(x + 1) = (3x + 2)(x + 1)
Do you mean 3x2+10x-8 if so then it is (3x-2(x+4) when factored
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
If the original is 2x + 3x2 + 6 + 5x3, you should rearrange the terms in order of exponent:5x3 + 3x2 + 2x + 6
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
3(x - 1)( x + 8)
3x2+13x-10 = (3x-2)(x+5) when factored
3x2+7-6 = (3x-2)(x+3) when factored
3x2-39x-90 = (3x+6)(x-15) when factored
3x2-7x+4 = (3x-4)(x-1) when factored
It is: (3x+1)(x-1)
If you mean: 3x^2 +31x +36 then it is (3x+4)(x+9) when factored
3x2 + 5x + 2 is a quadratic expression that can be factored as follows: 3x2 + 5x + 2 = 3x2 + 3x + 2x + 2 = 3x(x + 1) + 2(x + 1) = (3x + 2)(x + 1)
3x2 - 7x - 20 = (3x + 5)(x - 4)
3x2+x-2 = (3x-2)(x+1) when factored
Divide all terms by 3 and so x2+18x+81= (x+9)(x+9) when factored
Divide all terms by 3 gives x2+4x+4 = (x+2)(x+2) when factored