type you answer here!
x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
14xy - 21x + 7 '7' is a common factor to all three coefficients. So 'take it out'. Hence 7(2xy - 3x + 1) The rest of it , inside the brackets does not factor. However, I suspect the 'y' should be a 'power of 2' Hence 7(2x^(2) - 3x + 1) This factors to 7(2x - 1)(x - 1) Fully factored.!!!!
It is: 3x*(x+7)
(5x-6)(x-3)
21x2 - 31x + 8 = (3x - 8)(7x - 1)
y = 3x + 21x2 = 3x(1 + 7x)
To factor the expression 21x^35, you need to find the common factors of 21 and x^35. The factors of 21 are 1, 3, 7, and 21. The factors of x^35 are x, x^2, x^3, ..., x^35. Therefore, the factored form of 21x^35 is 21x*x^34 or 21x^(35-1).
To factor 4x^2 - 21x + 5, we look for two binomials in the form (Ax + B)(Cx + D) that multiply to give 4x^2 - 21x + 5. We can determine the values of A, B, C, and D by examining the factors of 4 and 5. The factored form is then (4x - 1)(x - 5).
i hope you mean (2x^2 + 21x + 49) you cant solve it its already in its lowest possible form
10x2 + 21x - 10 = 10x2 + 25x - 4x - 10 = 5x(2x + 5) - 2(2x + 5) = (2x + 5)(5x -2)
type you answer here!
x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
2x2+21x+49 = (2x+7)(x+7)
x2 - 21x = 72x2 - 21x - 72 = 0(x - 24) (x + 3) = 0x = 24x = -3
21x + 9 = 180 21x = 180 - 9 21x = 171 x = 171/21 x = 8.143
21x+452 = 32-84x 21x+84x = 32-452 105x = -420 x = -4