Well, since the nth term is 2n+6, therefore First term = 2(1)+6 =8
Second term is 2(2) +6 = 10
Third term is 2(3) +6 = 12
Hence, their some = S3=3(2(a)+(3-1)d)/2
====>3(2(8)+2(2))/2
====>3(20)/2=30
Which means that this is an arithmetic sequence where a=8 and d=2
What you need to do is replace (n) with the number of the term you want to find, and there is your answer.
5 first terms in n²+3
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
14112027
5, 11, 17, 23, 29
The 99th term would be a times r to the 98th power ,where a is the first term and r is the common ratio of the terms.
2,1,0 is th sequence of its terms
the first 4 terms of the sequence which has the nth term is a sequence of numbers that that goe together eg. 8,12,16,20,24 the nth term would be 4n+4
9, 17, 25, 33, 41
5, 8, 11, 14 and 17.
5 first terms in n²+3
no clue
nth term is 8 - n. an = 8 - n, so the sequence is {7, 6, 5, 4, 3, 2,...} (this is a decreasing sequence since the successor term is smaller than the nth term). So, the sum of first six terms of the sequence is 27.
If the nth term is n*7 then the first 5 terms are 7, 14, 21, 28, 35.
14112027
If the formula for additional terms was the summation of the term before it, the nth term of the series would be the sum of all terms prior. In other words it would be the summation of a through n minus 1.
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
The first four terms are 3 9 27 81 and 729 is the 6th term.