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Well, since the nth term is 2n+6, therefore First term = 2(1)+6 =8

Second term is 2(2) +6 = 10

Third term is 2(3) +6 = 12

Hence, their some = S3=3(2(a)+(3-1)d)/2

====>3(2(8)+2(2))/2

====>3(20)/2=30

Which means that this is an arithmetic sequence where a=8 and d=2

What you need to do is replace (n) with the number of the term you want to find, and there is your answer.

Q: What is the first 3 terms if the nth term is 2n plus 6?

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