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Well, since the nth term is 2n+6, therefore First term = 2(1)+6 =8
Second term is 2(2) +6 = 10
Third term is 2(3) +6 = 12
Hence, their some = S3=3(2(a)+(3-1)d)/2
====>3(2(8)+2(2))/2
====>3(20)/2=30
Which means that this is an arithmetic sequence where a=8 and d=2
What you need to do is replace (n) with the number of the term you want to find, and there is your answer.
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ā 13y ago
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