5
To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).
Given that the second differences of the sequence are a constant 2, the sequence can be modeled as a quadratic function. The general form of a quadratic sequence is ( an^2 + bn + c ). With the fourth term being 27 and the fifth term being 39, we can set up equations to find the coefficients. Solving these, we find that the first three terms of the sequence are 15, 21, and 27.
To find the first three terms of a sequence where the fifth term is 162, we can assume the sequence follows a specific pattern, such as an arithmetic sequence. For example, if we let the first term be ( a ) and the common difference be ( d ), the fifth term can be expressed as ( a + 4d = 162 ). By choosing ( a = 82 ) and ( d = 20 ), the first three terms would be 82, 102, and 122. However, many sequences could satisfy the condition, so the terms can vary depending on the assumed pattern.
The sequence defined by the formula ( n^2 + 3n ) can be calculated by substituting the first three positive integers for ( n ). For ( n = 1 ), the term is ( 1^2 + 3(1) = 4 ); for ( n = 2 ), it is ( 2^2 + 3(2) = 10 ); and for ( n = 3 ), it is ( 3^2 + 3(3) = 18 ). Therefore, the first three terms of the sequence are 4, 10, and 18.
The nth term of the sequence given by the formula (2 - n) can be found by substituting (n) with the first three positive integers: For (n = 1): (2 - 1 = 1) For (n = 2): (2 - 2 = 0) For (n = 3): (2 - 3 = -1) Thus, the first three terms of the sequence are 1, 0, and -1.
Which sequence? Oh, that one! The first three terms are 1, 2 and 72.
-2,-4,-6.
To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).
Given that the second differences of the sequence are a constant 2, the sequence can be modeled as a quadratic function. The general form of a quadratic sequence is ( an^2 + bn + c ). With the fourth term being 27 and the fifth term being 39, we can set up equations to find the coefficients. Solving these, we find that the first three terms of the sequence are 15, 21, and 27.
three
The sequence defined by the formula ( n^2 + 3n ) can be calculated by substituting the first three positive integers for ( n ). For ( n = 1 ), the term is ( 1^2 + 3(1) = 4 ); for ( n = 2 ), it is ( 2^2 + 3(2) = 10 ); and for ( n = 3 ), it is ( 3^2 + 3(3) = 18 ). Therefore, the first three terms of the sequence are 4, 10, and 18.
In lowest terms, three and one-ninth divided by one and two-fifths = 20/9 or 22/9
Each number in the sequence is 8 times the previous term, hence the next three terms are: 204.8, 1638.4 and 13107.2
The nth term of the sequence given by the formula (2 - n) can be found by substituting (n) with the first three positive integers: For (n = 1): (2 - 1 = 1) For (n = 2): (2 - 2 = 0) For (n = 3): (2 - 3 = -1) Thus, the first three terms of the sequence are 1, 0, and -1.
Three or more terms of a sequence are needed in order to find its nth term.
34-55-89 are.
First, in order ro find the next three terms in the sequence, you must find out the sequence. To do so, take 24 and subtract 15, now take the answer and subtract it from 15, which should equal 6. The sequence or the difference between all the numbers is 9. Now that we know the sequence, we can answer the question. Lets take 24 and add 9 to it, we come out with 33, now take 33 and add 9, which is 42 and add 9 to that which gives you 51. The next three terms are 33, 42 and 51