5
To find the first three terms of an arithmetic sequence with a common difference of -5, we first need the last term. If we denote the last term as ( L ), the terms can be expressed as ( L + 10 ), ( L + 5 ), and ( L ) for the first three terms, since each term is derived by adding the common difference (-5) to the previous term. Thus, the first three terms would be ( L + 10 ), ( L + 5 ), and ( L ).
The sequence defined by the formula ( n^2 + 3n ) can be calculated by substituting the first three positive integers for ( n ). For ( n = 1 ), the term is ( 1^2 + 3(1) = 4 ); for ( n = 2 ), it is ( 2^2 + 3(2) = 10 ); and for ( n = 3 ), it is ( 3^2 + 3(3) = 18 ). Therefore, the first three terms of the sequence are 4, 10, and 18.
Three or more terms of a sequence are needed in order to find its nth term.
34-55-89 are.
40.5, 60.75 and 91.125
Which sequence? Oh, that one! The first three terms are 1, 2 and 72.
-2,-4,-6.
three
In lowest terms, three and one-ninth divided by one and two-fifths = 20/9 or 22/9
Each number in the sequence is 8 times the previous term, hence the next three terms are: 204.8, 1638.4 and 13107.2
Three or more terms of a sequence are needed in order to find its nth term.
34-55-89 are.
First, in order ro find the next three terms in the sequence, you must find out the sequence. To do so, take 24 and subtract 15, now take the answer and subtract it from 15, which should equal 6. The sequence or the difference between all the numbers is 9. Now that we know the sequence, we can answer the question. Lets take 24 and add 9 to it, we come out with 33, now take 33 and add 9, which is 42 and add 9 to that which gives you 51. The next three terms are 33, 42 and 51
The sequence 9, 9, 9, 9 is an arithmetic sequence with a common difference of 0. Therefore, the next three terms of the sequence are also 9, 9, and 9.
10
1, -3, -7
40.5, 60.75 and 91.125