There are many types of rolling offsets. 2 common are rolling offset using 45 degree fittings and a rolling offset using any angle.
using 45's
Rise: elevation change
roll: run of the pipe moving to the left or right
Travel: the run of pipe to make the offset
Simple formula
Travel = SQRT((rise(squared) + Roll(squared) ) x 2)
rise = 10"
roll= 16"
Travel=?
travel= SQRT ( ((10 x 10) + (16 x 16)) x 2 )
travel= SQRT ( ((100) + (256)) x 2 )
travel= SQRT ( ( 356 ) x 2 )
travel= SQRT ( 712 )
Travel= 26.68333 or 26-11/16"
The problem can be split into two parts, rolling a 12, or rolling a 4 or less. This can be further broken down to rolling a 2, rolling a 3, rolling a 4, or rolling a 12. P(rolling 4 or less, or 12) = P(rolling 4 or less) + P(rolling 12) = P(rolling a 2) + P(rolling a 3) + P(rolling a 4) + P(rolling a 12) = 1/36 + 2/36 + 3/36 + 1/36 = 7/36
The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
There are 36 outcomes for rolling 2 dice, and there is 1 way that a 12 can occur which is 6,6. So, the probability of rolling the sum of 12 on 2 dice is 1/36.
Well there is 36 different possibilities with rolling 2 6 sided dice. The probability of rolling the sum of 10 with 2 die is 4/36 or 1/8 chance.
Probability of rolling an even number on a die is 1/2.
For rolling offsets with a rise of 17" and a roll of 65"s with 2 45s what degree are the 45s on
A rolling offset is generally an offset requiring a change in 2 directions. Eg. A horizontal offset and a vertical change in elevation. There is additional information required to answer the question. What is the angle of the fittings being used for offset? 15 deg. 30. 45? What is the change in elevation? If this is a flat (no change in elevation offset) using 45 deg., the offset dimension (7') is multiplied by 1.4142 which is the secant and cosecant of 45 deg. The result 7 ' x 1.4142 = 9'-10 13/16" Again, this result is for a flat run of pipe. If we have a rolling offset with a change in elevation of say 1'. We can use the Pythagorean theorem (A2 +B2 = C2) The result would be (1')2 + (9'-10 13/16")2 = 98.99812 sq. ft. The square root of 98.99812 is 9'-11 3/8"
If there are 2 circles of same size , offset by distance x what is the area of the overlap
2. Discuss the offset sections?
1 in 6 = rolling a 2 5 in 6 = not rolling a 2
Cinematech Nocturnal Emissions - 2005 Rolling Rolling Rolling--- 2-4 was released on: USA: 15 February 2006
Prob(Rolling 2 when rolling 1200 times) = 1 - Prob(not rolling 2 when rolling 1200 times) = 1 - (5/6)1200 = 1 [accurate to 95 decimal places] That is, it is virtually a certainty.
the chances of rolling a 2 each time during 1 set of 3 rolls is -1 in 216- sets. i believe the formula is: 1 in 6 - the chance of rolling a"2" then multiply the chances for each separate roll 1/6 x 1/6 x 1/6 = 1/216
The probability of rolling at least one 2 when rolling a die 12 times is about 0.8878. Simply raise the probability of not rolling a 2 (5 in 6, or about 0.8333) to the 12th power, getting about 0.1122, and subtract from 1.
The problem can be split into two parts, rolling a 12, or rolling a 4 or less. This can be further broken down to rolling a 2, rolling a 3, rolling a 4, or rolling a 12. P(rolling 4 or less, or 12) = P(rolling 4 or less) + P(rolling 12) = P(rolling a 2) + P(rolling a 3) + P(rolling a 4) + P(rolling a 12) = 1/36 + 2/36 + 3/36 + 1/36 = 7/36
The kinetic energy of a rolling ball is the sum of its translational kinetic energy and its rotational kinetic energy. For a rolling ball without slipping, the kinetic energy will be a combination of both types of energy. The formula to calculate the total kinetic energy is KE = 1/2 mv^2 + 1/2 IĻ^2, where m is the mass of the ball, v is its velocity, I is the moment of inertia, and Ļ is the angular velocity.
(frame no * page size) + offset value = physical add where frame value is the value present in the corresponding page number offset value is the last n bits of the logical address page no is the first m-n bits of logical address 2^m is the logical address 2^n is the page size