You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
The nth term is (2n - 12).
10
-34
The given sequence is an arithmetic progression.a = first term of A.P. = 10, d = common difference = an - an-1 = -4nth term of an A.P. is given by: an = a+(n-1)dPlugging in the values we get an = 10+(n-1)(-4) = 10 - 4n + 4 = 14 - 4n.
2n
forty
subtrahend or what
You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6
If this is an arithmetic problem, 10 is the "minuend" and 4 is the "subtrahend".
The nth term is (2n - 12).
2n - 12
It is: 2n+4
10
-34
The given sequence is an arithmetic progression.a = first term of A.P. = 10, d = common difference = an - an-1 = -4nth term of an A.P. is given by: an = a+(n-1)dPlugging in the values we get an = 10+(n-1)(-4) = 10 - 4n + 4 = 14 - 4n.
14