The nth term of that series is (24 - 6n).
If you mean: 6 12 18 24 then the nth term is 6n
By varying the parameters of a quartic polynomial, the nth term can be made whatever you like. But, taking the simplest solution, Un = 2 - 4n for
The nth term of an AP with initial term a (= u{1}) and common difference d is given by: u{n} = a + (n - 1)d In this case: a = 6 d = (12 - 6) = 6 → u{n} = 6 + (n - 1)6 But this can be simplified: u{n} = 6 + (n - 1)6 = 6 + 6n - 6 = 6n
1, 3, 6, 10, ... The nth term is n*(n+1)/2
The nth term is (2n - 12).
nth term= 6 + (n-1) (2)
2n - 12
The nth term of that series is (24 - 6n).
If you mean: 6 12 18 24 then the nth term is 6n
It is: nth term = -4n+14
The nth term is 18 -3n and so the next term will be 3
3n
3n
The nth term in this arithmetic sequence is an=26+(n-1)(-8).
The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)
24 - 6n