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Q: What is the greatest possible 3 digit no. for which the sum is 10?

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The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.

91

46

this is a guess and check problem. answers is 1009. 999 - 10 = 989 lets try one less (998) 998 -9(1 digit) is not possible, lets try one more (1000) 1000(4 digit) - 11 is not possible so only possible solution is (999,10) Answers is 999+10 = 1009

There are 30,240 different 5-digit numbers. Math: 10*9*8*7*6 1st digit has 10 possible choices (0-9) 2nd digit has 9 possible choices (one of the digits was used in the 1st digit) 3rd digit has 8 possible choices 4th digit has 7 possible choices 5th digit has 6 possible choices

Related questions

All nines 9,999,999,999

Guessing 10 000. The zeros count as a digit. The greatest possible is 99 999. =)

i'll... say both?highest: 99+99+99=297lowest: 10+10+10=30

for (sum=0; n!=0;) sum+=n%10, n /= 10;

The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.

1,000,009

10 + 15 = 25. the tens digit of 25 is 2

There are 6 solutions in all.The middle digit must be 0 , 2 or 4.If the middle digit is 0, then the first two digits must sum to 3. There are three possible solutions: 12, 21 and 30.If the middle digit is 2, then the first two digits must sum to 2. There are two possible solutions: 11 and 20.If the middle digit is 4, then the first two digits must sum to 1. There is one possible solutions: 10.

91

#include<stdio.h> int main() { int s,sum; long num; printf("enter the no:"); scanf("%ld",&num); sum=num; while(sum>10) { sum=0; while(num!=0) { s=num%10; sum=sum+s; num=num/10; } num=sum; } printf("the single digit sum is :%d",sum); return 0; }

46

Smallest 2 digit number is 10. 10 + 99 = 109

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