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If the two adjacent sides of a triangle are 3' and 4' what is the length of the hypotenuse?
If the two adjacent sides of a triangle are 3' and 4', the hypotenuse is: 5'
How do you calculate the hypotenuse of a triangle?
a2+b2=c2 Example: a=4 b=3 4 times 4= 16 3 times 3= 9 16+9= 25 square root of 25= 5 hypotenuse= 5
Formula to calculate the value of the hypotenuse?
a2+b2=c2 Example: a=4 b=3 4 times 4= 16 3 times 3= 9 16+9= 25 square root of 25= 5 hypotenuse= 5
One leg of a right triangle measures 4 inches and the other 6 inches how long is the hypotenuse?
The length of the hypotenuse = √(4^2 + 6^2) = √52 ≈ 7.21 in
If sinA equals 1 by 3 evaluate cosA cosecA plus tanA secA?
SinA = 1/3 = Opposite/HypotenuseTherefore taking Opposite to be 1cm and Hypotenuse to be 3cm.Therefore Adjacent side = Root of 32 - 12= root 8CosA = Adjacent/Hypotenuse = root8 / 3CosecA = Hypotenuse/Opposite = 3/1TanA = Opposite/Adjacent = 1 / root8SecA = Hypotenuse/Adjacent = 3 / root8Therefore,(CosA.CosecA) + (TanA.SecA) = (root8 / 3 . 3 / 1) + (1 / root8 . 3 / root8)= (root8) + (3 / 8)= 2(root2) + (3 / 8)
