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If you restrict yourself to integers, it's 24. If not, it's 22.63 rounded to two decimal places.

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Q: What is the least perimeter of a rectangle with an area of 32?
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Related questions

What it the least perimeter of a rectangle with an area of 32 square feet?

47


What is the least perimeter of a rectangle with an area of 32 ft.²?

If you restrict yourself to integers, the answer is 24 feet.


What is the least perimeter of a rectangle with an area of 32 square ft?

The least perimeter is attained when the rectangle is, in fact a square. A square with an area of 32 square feet will have sides of sqrt(32) = 4*sqrt(2) ft. So the perimeter of the square will by 4*4*sqrt(2) = 16*sqrt(2) = 22.63 feet, approx.


What is the area of a rectangle with a perimeter of 24 and a length of 8?

32


How do you find the area of a rectangle with a perimeter of 36m?

how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.


What would be a greater perimeter but a smaller area to a question of 24 and a area of 27?

Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15


What is the perimeter and area of a rectangle with 5 in length and 11 in width?

Perimeter = 32 inches. Area = 55 square inches.


What is the area ad perimeter of a rectangle 27cm wide 32cm long?

Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm


Area of rectangle perimeter 32 units width 6 units?

The area of a rectangle with a perimeter of 32 units and a width of 6 units the area is 80 square units.Improved Answer:-Area = 6*10 = 60 square unitsPerimeter = 6+6+10+10 = 32 units


What is the perimeter and area of rectangle 14cm by 32 cm?

To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm. To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.


Two polygons that have the same perimeter but a different area?

For example, a 1x15 rectangle and a 2x14 rectangle. They both have perimeter of 32, but they have areas of 15 and 28, respectively.


What is the dimensions of a rectangle for the number 32?

It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?