If you restrict yourself to integers, the answer is 24 feet.
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
Perimeter = 32 inches. Area = 55 square inches.
Perimeter = 2*(10+6) = 2+16 = 32 metres.
A square with a perimeter of 32 inches has an area of 64 square inches.
47
If you restrict yourself to integers, the answer is 24 feet.
The least perimeter is attained when the rectangle is, in fact a square. A square with an area of 32 square feet will have sides of sqrt(32) = 4*sqrt(2) ft. So the perimeter of the square will by 4*4*sqrt(2) = 16*sqrt(2) = 22.63 feet, approx.
32
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
Perimeter = 32 inches. Area = 55 square inches.
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm
The area of a rectangle with a perimeter of 32 units and a width of 6 units the area is 80 square units.Improved Answer:-Area = 6*10 = 60 square unitsPerimeter = 6+6+10+10 = 32 units
For example, a 1x15 rectangle and a 2x14 rectangle. They both have perimeter of 32, but they have areas of 15 and 28, respectively.
It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?
If the perimeter is 32 sq cm, there is a very serious problem since the perimeter is a linear measure, not an area! Leaving that aside, the length of the rectangle is 10 cm and the breadth is 6 cm.