Q: What is the length of a diagonal line in a rectangle 30 feet by 20 feet?

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Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal

right triangles and

It depends on the inclination of the line of cross section. If it is at an incline to the sides and diagonal, the cross section is a point which becomes a line that increases in length, reaches a maximum, remains at that length and then shrinks back to a point. If it is parallel to a diagonal, the cross section is a point which becomes a line that increases in length, reaches a maximum and then shrinks back to a point. If it is parallel to a side, the cross section is a line of constant length.

Just find the midpoint of opposite corners Consider the rectangle with sides of length a and b. The length of a diagonal is then sqrt(a2+b2) The two diagonals cross at the midpoint or where the length of the line from one vertex to the center is one half of a diagonal or (0.5)[sqrt(a2+b2)]. 1- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and you have Point B(XB, YB) corresponding to the lower right coordinate of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated: XC = XA + (XB-XA)/2 YC = YA - (YA-XB)/2 2- Consider you have Point A(XA,YA) corresponding to the upper left coordinate of the rectangle and the width (W) and height (H) of the rectangle, then, coordinates of the center Point C (XC, YC) is calculated: XC = XA + (W)/2 YC = YA - (W)/2

If the square then the area = side * side.A = 50therefore side = square root of 50The longest line that fits in a square is a diagonal line from corner to corner. The length of this can be calculated using pythogoras' theorem.A2 + B2 = C2For this specific square A = B = squareroot of 50So 50 + 50 = C2C2 = 100C = 10The longest line is 10 feet

Related questions

The diagonal is approximately 38.42 feet.

Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal

Approximately 15.62 feet.

60 feet Solved with the help of Pythagoras' theorem

The diagonal line of a rectangle for example is greater than its length.

The diagonal length is about 18.44 inches.

The diagonal line forms two triangles, each with one side 34 feet long and one side 30 feet long. Use Pythagorean Theorem to find the length of the diagonal line which is the hypotenuse of the triangles. a^2 + b^2 = c^2 Where a and b are the sides of the triangle and c is the hypotenuse. (34)^2 + (30)^2 = c^2 1156 + 900 = c^2 2056 = c^2 45.34 = c So, the diagonal line is 45.34 feet.

No. The diagonal through a rectangle can be computed via the Pythagorean theorem: c2 = a2 + b2 where c is the diagonal length and a and b are the horizontal and vertical lengths of the rectangle.

d = 11.5 inches.

Use Pythagoras' theorem to find the length of the diagonal of a rectangle.

You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com

To trisect a rectangle first draw the two diagonals (lines going from the top left corner, to the bottom right and top right to bottom left.) Where those two diagonals intersect is the center of the rectangle. Next, draw a line through the center of the rectangle that is parallel to the top and bottom of the rectangle. this should divide the rectangle into two halves. Next draw the diagonal for the top half of the rectangle (A line from the top left corner, to the middle of the right side.) Where this diagonal intersects with the diagonal of the diagonal of the entire rectangle is 1/3 the length. Repeat the previous step for the bottom half of the rectangle. The line connecting the top intersection, and the bottom intersection is the trisection line.