Pythagoras' theorem shows the side you are looking for, the hypotenuse of the right angles triangle is the root of the sum of the other two sides, so it is root(10 squared+ 10 squared)= root(200)=10*root2 or 14.1421356 inches
Divide the length of the diagonal of a square by 1.4142 (which is the square root of 2) to find the length of a side. Similarly, to find the length of the diagonal of a square, multiply the length of a side by 1.4142.
If the side of the square is s inches, then the diagonal is s*sqrt(2) So s*sqrt(2) = 250 s = 250/sqrt(2) = 176.78 inches.
If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.
Length of diagonal = Square root ( (side length 2) * 2 )
8*sqrt(2) The diagonal of the square would be the hypotenuse of the right triangle formed by two of the sides of the square.
The diagonal length = 7.07 inches.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
Each side is sqrt 72 ie 8.49 in
Divide the length of the diagonal of a square by 1.4142 (which is the square root of 2) to find the length of a side. Similarly, to find the length of the diagonal of a square, multiply the length of a side by 1.4142.
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
The length of one side of a square with a 16-centimeter diagonal is: 11.31 cm
If the side of the square is s inches, then the diagonal is s*sqrt(2) So s*sqrt(2) = 250 s = 250/sqrt(2) = 176.78 inches.
Each side of the square is 20 inches and by using Pythagoras' theorem its diagonal is 20 times the square root of 2 which is about 28.284 inches rounded to 3 decimal places.
If the circle is inscribed in the square, the side length of the square is the same as the diameter of the circle which is twice its radius: → area_square = (2 × 5 in)² = 10² sq in = 100 sq in If the circle circumscribes the square, the diagonal of the square is the same as the diameter of the circle; Using Pythagoras the length of the side of the square can be calculated: → diagonal = 2 × 5 in = 10 in → side² + side² = diagonal² → 2 × side² = diagonal² → side² = diagonal² / 2 → side = diagonal / √2 → side = 10 in / √2 → area _square = (10 in / √2)² = 100 sq in / 2 = 50 sq in.
If the length of a side of the square is S units then the diagonal is S*sqrt(2) units in length.
To find the area of a square with a diagonal of 14, we first need to determine the length of one side of the square. Using the Pythagorean theorem, we can calculate that the side length is 7√2. Then, we can find the area of the square by squaring the side length, which gives us 98 square units.