If the side of the square is s inches, then the diagonal is s*sqrt(2)
So s*sqrt(2) = 250
s = 250/sqrt(2) = 176.78 inches.
The square's sides will be the sqrt 2 = about 1.414 inches.(NOTE that this only happens when the circle is 2 inches in diameter. For a circle 3 inches in diameter, the diagonal measurement 3 = (sq rt 2) s and s = about 2.122 inches, not the square root of 3)The largest square will have a DIAGONAL the same length as the DIAMETER of the circle. This is clear when you imagine that it is the largest dimension of any square. With the diagonal length being the hypotenuse of the two right triangles that form the square, the diagonal length equals the square root of the sum of the squares (of the two sides of the square)diagonal = (sq rt 2) x sidediameter = sq rt (s^2 + s^2).2 inches = sq rt (2 s^2)2 inches - (sq rt 2) x s2 inches = 1.414 sand s = 1.414
The diagonal measurement of an 8 ft square is: 11.31 feet.
Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.
You use the Pythagorean Theorem, which says that the square of the hypotenuse of a right triangle is the sum of the squares of the other two sides. Two adjacent sides of a square (or any rectangle) together with a diagonal form a right triangle. In the case of a square, the triangle is isosceles. Calling the length of a side of the square (17 inches) one unit, the theorem tells us that the hypotenuse is the square root of 2 units. Therefore the diagonal of the square is 17 times the square root of 2 inches, which is about 24 inches.
The diagonal measurement of an 18 x 18 square is: 25.46 units.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
The diagonal length is about 20.59
The diagonal length = 7.07 inches.
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
94x96 is not a correct measurement of a square.
A square with 2-inch sides has a diagonal of: 2.828 inches.
The diagonal is 14 inches.
Using Pythagoras the diagonal is 20 times square root of 2
Given a diagonal of 7.125 inches, the square has the following measurements:Side lengths of 5.038 inchesPerimeter of 20.15 inchesVolume of 25.38 inches2
Approximately 10 inches.
-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.
The square's sides will be the sqrt 2 = about 1.414 inches.(NOTE that this only happens when the circle is 2 inches in diameter. For a circle 3 inches in diameter, the diagonal measurement 3 = (sq rt 2) s and s = about 2.122 inches, not the square root of 3)The largest square will have a DIAGONAL the same length as the DIAMETER of the circle. This is clear when you imagine that it is the largest dimension of any square. With the diagonal length being the hypotenuse of the two right triangles that form the square, the diagonal length equals the square root of the sum of the squares (of the two sides of the square)diagonal = (sq rt 2) x sidediameter = sq rt (s^2 + s^2).2 inches = sq rt (2 s^2)2 inches - (sq rt 2) x s2 inches = 1.414 sand s = 1.414