The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.
So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).
The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.
So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).
The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.
So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).
The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.
So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).
Density = Mass/Volume = 120 grams/7 ml = 17.142857... grams per ml.
6.496 g
8.20 mL of mercury would have a mass of 111 grams or 0.245 pounds.
1.12g/ml
Approx 7.42 grams.
15.5 gram ethanol x 1 mL/0.789 (density) = 19.65 mL the density of ethanol is 0.789g/mL
Divide by the density of ethanol.Assuming that it is a total mass of 60.354 grams, and the density of ethanol is 0.789 grams per cm3 (or grams per mL), then the volume of that much ethanol is:60.354 grams ÷ 0.789 grams/mL = 76.494 mL
Assuming the density of ethanol is 0.789 g/mL at room temperature, the mass of 63.0 mL of ethanol would be 49.707 grams.
At STP, pure ethanol has density 0.789g/mL. 25 mL will have mass25 (mL) * 0.789 (g/mL)=19.725 g. Round this to 19.7g for three significant figures.
This is not a valid conversion; milligrams (mg) and grams (g) are measures of weight or mass while milliliters (mL or ml) measure volume.
Benzene is more dense than ethanol. This can be determined by calculating the density of each liquid using the formula density = mass/volume. In this case, benzene's density is higher than ethanol's because for the same volume, benzene has a higher mass.
The density of ethanol is approximately 0.789 g/mL. Therefore, to calculate the weight of ethanol in a 200.0 mL container, you would multiply the volume by the density: 200.0 mL * 0.789 g/mL = 157.8 grams.
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
5
The answer is 0,065 g.
The volume of 495g of ethanol can be calculated by dividing the mass by the density of ethanol. The density of ethanol is approximately 0.789 g/ml at room temperature. Therefore, the volume of 495g of ethanol would be 495g / 0.789 g/ml ≈ 627 ml.
The mass of the substance is 20 grams in a 10 ml sample. Therefore, the substance has a density of 2 grams/ml. For a 200 ml sample of the same substance, the mass would be 400 grams (200 ml x 2 grams/ml).