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The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.

So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).



The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.

So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).



The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.

So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).



The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.

So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).

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11y ago

The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.

So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).

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Q: What is the mass in grams of 147 mL of ethanol?
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The density of ethanol is approximately 0.789 g/mL. To find the volume of ethanol with a mass of 15.5 grams, divide the mass by the density: 15.5 g / 0.789 g/mL ≈ 19.6 mL.


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