6.496 g
The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).
Density = Mass/Volume so Volume = Mass/Density. Having said that, density is not measured in grams so it cannot be 0.789 grams. As a result, the question cannot be answered.
Volume = Mass/Density = 45.6/10.5 = 4.34 millilitres.
10.1
Density is grams per cm3. 615/105 = 5.86 g/cm3
Divide by the density of ethanol.Assuming that it is a total mass of 60.354 grams, and the density of ethanol is 0.789 grams per cm3 (or grams per mL), then the volume of that much ethanol is:60.354 grams ÷ 0.789 grams/mL = 76.494 mL
No, hexane is less dense than ethanol- hexane has a density of 0.6548g/mL and ethanol has a density of 0.789g/mL, so hexane will float on top of ethanol.
15.5 gram ethanol x 1 mL/0.789 (density) = 19.65 mL the density of ethanol is 0.789g/mL
The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).
The density of ethanol is approximately 0.789 g/mL. Therefore, to calculate the weight of ethanol in a 200.0 mL container, you would multiply the volume by the density: 200.0 mL * 0.789 g/mL = 157.8 grams.
Benzene is more dense than ethanol. This can be determined by calculating the density of each liquid using the formula density = mass/volume. In this case, benzene's density is higher than ethanol's because for the same volume, benzene has a higher mass.
Assuming 12% alcohol content in wine, there would be 84 grams of ethanol in a 0.7 liter bottle of wine. This is calculated by multiplying the volume of wine by the alcohol content percentage and the density of ethanol.
Assuming the density of ethanol is 0.789 g/mL at room temperature, the mass of 63.0 mL of ethanol would be 49.707 grams.
It would depend on the quantity: mass=volume x density; the density of ethanol at 20 0C is 0789 g/cm3.
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
There are .098 liters in 98 grams of ethanol.
First, calculate the weight of 1 drop of ethanol: 0.60 grams / 15 drops = 0.04 grams per drop. To dispense 1.0 mL of ethanol, you will need 1.0 mL / 0.80 g/mL = 1.25 grams. Finally, to find the number of drops, divide the total weight by the weight per drop: 1.25 grams / 0.04 grams per drop = 31.25 drops, round up to 32 drops.