6.496 g
The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).
Density = Mass/Volume so Volume = Mass/Density. Having said that, density is not measured in grams so it cannot be 0.789 grams. As a result, the question cannot be answered.
Density = Mass/Volume so the density is 120/40 grams per cm3 = 3 grams per cubic cm.
Volume = Mass/Density = 45.6/10.5 = 4.34 millilitres.
10.1
Divide by the density of ethanol.Assuming that it is a total mass of 60.354 grams, and the density of ethanol is 0.789 grams per cm3 (or grams per mL), then the volume of that much ethanol is:60.354 grams ÷ 0.789 grams/mL = 76.494 mL
15.5 gram ethanol x 1 mL/0.789 (density) = 19.65 mL the density of ethanol is 0.789g/mL
The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).The density of ethanol at 20 deg C and normal presure is 0.789 g/mL.So the mass of 147 mL is 147*0.789 = 116.0 grams (approx).
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
you need to state the % alcohol of the wine (%vol/vol). find out ethanol's density and then you can calculate the weight ethanol per litre, /1000,x700 per 700ml.
There are .098 liters in 98 grams of ethanol.
density
Ethanol (USP grade) has a density of 0.810. From here we have to use the formula: d=m/v, where d is density, m, mass and v, volume. Solving for volume, we have v=m/d, therefore: v= 15/0.810 = 18.52 mL of ethanol are equivalent to 15g.
Ethanol is the solvent and sucrose is the solute.
Osmium has a density of 22.61 grams. Iridium has a density of 22.56 grams. Mercury has a density of 13.6 grams.
C6H12O6 (180.16 g/ mol) ---> 2C2H5OH (46.07 g/mol) + 2 CO2 600.4 g glucose @ 92.14 g ethanol / 180.16 g glucose = 307.06 grams of ethanol can be produced 307.06 grams of ethanol @ 0.789g/ml = 389.2 millilitres ========= your answers: 307 grams of ethanol & 0.389 litres of ethanol
The density of calcium is 1.55g/cc (1.55 grams per cubic centimeter). The mass depends on how large the quantity of calcium is.