Q: What is the maximum value of a binary number with 8 bits?

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To get the 2s complement, change all 1 bits to 0s and all 0 bits to 1s, and add 1 to the result. So the 2s complement of the 8-bit binary number 10001011 is the binary integer 01110101. If you want that in decimal, then remember that each place value column is twice the value of the place value column to its right, and the rightmost place value column for an integer is 1. Thus 01110101 in decimal is 64 + 32 + 16 + 4 + 1 = 117 (And 10001011 as a signed 8-bit binary integer represents the decimal integer -117.)

255 as a decimal number (also known as a base 10 number) = 11111111 in binary (also known as a base 2 number). In binary, each digit is known as a bit, and 8 bits are known as 1 byte. 255 is the largest (positive) number you can make in binary using only 8 bits (1 byte).

65536

Binary bits are necessary to represent 748 different numbers in the sense that binary bits are represented in digital wave form. Binary bits also have an exponent of one.

Related questions

4294967295

The largest possible value using 8 bits in binary is actually quite simple. Binary is a numerical system that only uses 2 numbers (1 and 0) to determine value. Our system is decimal. (0-9) Now, a 'bit' is one number from the binary system. It can either be 1 or 0. So, 8 bits means using 8 digits in binary. 1 is greater than 0, so the largest value is 11111111. (8 'one's)

It is a binary digit and computers use it to store and process data. A single binary unit is called a bit which stands for binary digit. Computer memory is measured in bytes. One byte is made up of eight bits.

the largest binary number is 1.84467440737e19. to figure this out you put 2 to the exponent of the certain amount of bits. Eg: 2^64 equals the binary number

A bit is a single digit of a binary number.

A binary number containing eight bits is referred to as one "Byte". A binary number containing four bits is referred to as one "Nibble".

4 bits

It is a binary number where the sign, either plus or minus, can be declared. One Bit is given over to act as the sign, being either 1 or 0, with the rest of the bits acting as the actual value.

11b which is 1*2 + 1*1 = 3 would be for two bits. But a byte is 8 bits, so 2 bytes is 16 bits. The largest binary number is [2^16 - 1], which is 65535 (base ten)

My initial guess is as follows: binary code will render 2 possible digits, either 0 or 1. If there are 32 digits with two possible outcomes per digit then you will find the answer by calculating 2 to the 32nd power. The answer I got was 4294967296 seconds. Edit: The maximum number which can be represented by a binary string is always 2^n where n is the number of bits in the string.

To achieve the answer to what the decimal equivalent of the largest binary number with five places (or bits) is, work this equation: The formula is 2_ -1 where n is the number of bits. That will get you where you need to be.

000000 is the lowest number in a 6 bit unsigned binary number (meaning the high order bit is not the sign bit). If it is a signed number then the lowest number would be represented by 100000 which is equivalent to -32 in decimal. Highest unsigned number in 6 bits is decimal 63. Highest signed number in 6 bits is decimal 31.