5
One standard deviation for one side will be 34% of data. So within 1 std. dev. to both sides will be 68% (approximately) .the data falls outside 1 standard deviation of the mean will be 1.00 - 0.68 = 0.32 (32 %)
84% To solve this problem, you must first realize that 66 inches is one standard deviation below the mean. The empirical rule states that 34% will be between the mean and 1 standard deviation below the mean. We are looking for the prob. of the height being greater than 66 inches, which is then 50% (for the entire right side of the distribution) + 34%
34 + 23 = 57
The absolute value of a number which is not negative is the same as the number.
Mean (Average) means to add all the terms together, and then divide by the number of terms, which is '8'. ( 21 + 23 + 27 + 28 + 32 + 32 + 34 + 43) / 8 => 240/8 = 30 The Mean.!!!!
The mean absolute deviation is 8.22
To calculate the mean absolute deviation (MAD), first, find the mean of the data set: (16 + 19 + 20 + 22 + 26 + 34 + 35 + 39) / 8 = 24. Next, calculate the absolute deviations from the mean: |16-24|, |19-24|, |20-24|, |22-24|, |26-24|, |34-24|, |35-24|, |39-24|, which results in 8, 5, 4, 2, 2, 10, 11, and 15. The average of these absolute deviations is (8 + 5 + 4 + 2 + 2 + 10 + 11 + 15) / 8 = 7.125. Thus, the mean absolute deviation is 7.125.
The standard deviation of a single value, such as 34, is not defined in the traditional sense because standard deviation measures the spread of a set of data points around their mean. If you have a dataset that consists solely of the number 34, the standard deviation would be 0, since there is no variation. However, if you're referring to a dataset that includes 34 along with other values, the standard deviation would depend on the entire dataset.
49.30179172 is the standard deviation and 52 is the mean.
The standard deviation of 20 22 26 28 34: σ=5.4772
34° 23′ 5.71″ N, 109° 16′ 23.19″ E34.384919, 109.273108
34
34 and -34.
23% of 34= 23% * 34= 0.23 * 34= 7.82
One standard deviation for one side will be 34% of data. So within 1 std. dev. to both sides will be 68% (approximately) .the data falls outside 1 standard deviation of the mean will be 1.00 - 0.68 = 0.32 (32 %)
84% To solve this problem, you must first realize that 66 inches is one standard deviation below the mean. The empirical rule states that 34% will be between the mean and 1 standard deviation below the mean. We are looking for the prob. of the height being greater than 66 inches, which is then 50% (for the entire right side of the distribution) + 34%
mean median and mode of 28 54 34 50 34 First of all place the numbers in Rank Order. 28,34,34,50,54. I'll do then in reverse order. MODE ; is the number/term that is most frequent, which is '34'. MEDIAN : is to absolute middle number. Out of the five terms, the second '34' is the absolute middle term, so it is the median. MEAN : Is to summ all the terms and divide by the numbers of terms. Hence ( 28+34+34+50+54 ) / 5 = 200/5 200/5 = 40 THe mean.