10+9-8-7+6 = 10
The mean (or average) of 8, 9, and 10 is 9.
6.9 = 69⁄10 or 6 9⁄10
If you mean between 1 and 10 inclusive, then there's 10: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 If you mean exclusive, then there's 8: 2, 3, 4, 5, 6, 7, 8, 9 If you mean inclusive of one of the boundaries, then there's 9: 1, 2, 3, 4, 5, 6, 7, 8, 9 Including decimal places, then no matter what inclusive method or otherwise, there is an infinite number of numbers between one and ten.
It is: 9/11 divided by 10/6 = 27/55 in its lowest terms
8.29
'Mean' is the average of a range. (6+9+7+3+10+9)÷6=7.333333333 (7.33 to two decimal points).
8mean = (9+3+8+10+12+6)/6= 48/6= 8
6
8.
Mean: 9 Median: 8.5 Mode: 14, 6, 8, 10, 9, 5, 7, 13
5, 6, 9, 10, & 10
To find six numbers with a mean (average) of 9, we can choose numbers such that their sum equals 6 multiplied by 9, which is 54. Here's one possible set of numbers: 10 10 9 9 8 8 The sum of these numbers is 54, and when you divide the sum by 6 (the number of values), you get the mean of 9.
Mean = (9 + 10 + 2 + 5 + 5)/5 = 31/5 = 6.2
Close but not exactly. The mean is 474/9 . If 373 was a typo and it's supposed to be another 3, then the mean is 61/3 .
The arithmetic mean of 10, 11, and 6 is 9. Add them together then divide by 3.
There cannot be such a set.If the mean is 10, the mode is 6 and the median is 9, the range must be at least 8.5.If the mode is 6, the median is 9 and the range is 8, the mean must be less than 9.8.