The answer depends on what you wish to measure: the area, the number of sides, the number of vertices, the sum of the interior angles, the sum of exterior angles, ...
The question is hopelessly underspecified.
the sum of the interior angles of a 35-gon.
9000
3,600°
6120 degrees
Sum of interior angles of a n-gon is 180*(n-2) So for a 10-gon (decagon), the sum would be 180*8 = 1440 degrees. That is true whether the polygon is convex or not (as long as its sides do not intersect).
It is 8 x180=1440 degrees. Take an n-gon and the measure of the interior angles is (n-2)x180 degrees.
the sum of the interior angles of a convex 45-gon is 7740.
The sum of the exterior angle of ANY polygon is 360 degrees.
The sum of the interior angles of a n-gon is (n-2)*180 degrees. Convexity does not matter. So for a 17-gon, the sum would be 15*180 = 2700 degrees.
the sum of the interior angles of a 35-gon.
The sum of the exterior angles of any convex polygon is always 360 degrees. The sum of the interior angles of any convex n-gon is (n-2) * 180 degrees, because any convex n-gon can be represented as n-2 triangles, and the sum of the interior angles of a triangle is 180 degrees.
9000
3,600°
Exterior angle = 360/80 = 4.5 degrees. Interior angle = 180 - 4.5 = 175.5 degrees. And, a regular polygon has to be convex.
The total internal angles of an n-gon are given by pi*n-2pi. The individual angles, therefore, are given by (pi*n-2pi)/n For a regular convex n=31, the interior angles are each 9.233 radians to 4 sf.
Yes
6120 degrees