Both are 4.
1, 2, 2, 3, 4, 4, 5, 7, 8 Mean: 4 Median: 4 Mode: 2 and 4
The data {1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 7} has: Median: Thee are 16 data items, so the median is the mean average of the middle two, ie the 8th and 9th numbers: median is (3 + 3) / 2 = 3 Mean: (1 + 1 + 2 + 2 + 2 + 3 + 3 + 3 + 3 + 4 + 4 + 4 + 5 + 5 + 6 + 7) ÷ 16 = 55 ÷ 16 = 37/16 = 3.4375
definantly, yes Of course. 1, 2, 3, 40, 50, 60, 82 Mean = 34 Median = 40
mode- 5 median- 5 mean- 4.8
They quick answer is YES!Here is an example.Before we begin let quickly recap what the we mean by "mean", "median", "mode" and "range":[MEAN] - The sum of all the values, divided by the total number of values.[MEDIAN] - The middle value when the data is arranged in numerical order.[MODE] - The most common value in a data set.[RANGE] - The difference between the highest and lowest values in the set.If we had the following numbers 1, 2, 2, 2, 3,The [MEAN] would be: TWO= 1+2+2+2+3/5 = 10/5 = (2)The [MEDIAN] would be: TWO= 1 2 (2) 2 3 = (2)The [MODE] would be: TWOThe most common value is (2)The [RANGE] would be: TWOrange = (highest - lowest) = (3-1) = (2)Therefore; Mean, Median, Mode and Range = (2)So the Mean, Median, Mode and Range can all be the same number![Answered by F:A:W:B:Y] - (As always, glad to help)
mean= 2, mode= 1 and 3, median= 3, and range= 2
1, 1, 1, 1, 2, 2, 2, 3, 3, 4, 6, 8, 10, 12 The mean is 4 The median is 2.5 The mode is 1
I am guessing you are asking for an example of a set of numbers with these properties. Let's start with 5 numbers, so the median will be the middle number; say 1, 2, 3, 4, 5. The median is 3, but so is the mean. Now let's replace the 5 with 10. The median is still 3, but the mean is 4. To make the mode less than 3, let us change the 2 into a 1. Now the median is still 3, the mode is 1, and the mean is 3.8. So 1, 1, 3, 4, 10 will work.
1, 2, 2, 3, 4, 4, 5, 7, 8 Mean: 4 Median: 4 Mode: 2 and 4
Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6Mean = 4 Median = 3Mode = 2 and 3Range = 6
The median average is the middle number when the numbers are listed in increasing order. For example, the median of {1, 2, 3, 8, 9} is 3. If there is an even number of data items, the median is the mean average of the middle two numbers (add them together and divide by 2). For example, the median of {1, 2, 4, 5, 6, 7) is the mean of 4 & 5 = (4 + 5)/2 = 4.5
The data {1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 7} has: Median: Thee are 16 data items, so the median is the mean average of the middle two, ie the 8th and 9th numbers: median is (3 + 3) / 2 = 3 Mean: (1 + 1 + 2 + 2 + 2 + 3 + 3 + 3 + 3 + 4 + 4 + 4 + 5 + 5 + 6 + 7) ÷ 16 = 55 ÷ 16 = 37/16 = 3.4375
definantly, yes Of course. 1, 2, 3, 40, 50, 60, 82 Mean = 34 Median = 40
It depends on the data set, but if you take the data set 1,2,3 2 is the median and to find the mean you have to add all the numbers and divide by the number of items so 1+2+3=6 and 6 divided by 3= 2 now the median is 2 and the mean is 2 so this is when they can be the same
mode- 5 median- 5 mean- 4.8
Yes.Two ways:the data contains non-integer items, eg the median of {1, 1.3, 1.567, 2.4, 5} is 1.567;the data contains an even number of data items. In this case, the median is the mean average of the middle two, which may not be an integer, eg the median of {1, 2, 3, 4} is the mean average of {2, 3} = (2+3)/2 = 2.5
Mean: 3.857 Median: 3 Mode: 1, 3, 6 Range: 6