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What is the midpoint of (-4 6) and (4 -2)?
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What is the center of the circle with the endpoints of the diameter at -2 8 and 6 4?
centre is the midpoint of the line → centre = ((-2 + 6)/2, (8 + 4)/2) = (2, 6)
For a line segment one endpoint is -8 10 and the midpoint of - 2 6 Find the coordinates of the other endpoint x1 y1?
The midpoint is going to have an x and y value halfway between those of the two endpoints. The midpoint has an x value 6 higher than the first endpoint and a y value 4 lower. Just continue this pattern to get the other endpoint. (-2+6, 6-4)=(4, 2) The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2] By substituting the given values into the formula we have: (x1 + -8)/2 = -2 and (y1 + 10)/2 = 6 x1 - 8 = -4 and y1 + 10 = 12 x1 -8 + 8 = -4 + 8 and y1 + 10 - 10 = 12 - 10 x1 = 4 and y1 = 2 Thus, the other endpoint is (4, 2).
What is the midpoint of (-3 4) and (-6 -1)?
If R = (xr, yr) and P = (xp, yp) then the midpoint is [(xr + xp)/2, (yr + yp)/2].
What is the midpoint of coordinate 3 -6 and -5 2?
Midpoint of (3, -6) and (-5, 2) = [(3-5)/2, (-6+2)/2] = (-1, -2)
