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centre is the midpoint of the line → centre = ((-2 + 6)/2, (8 + 4)/2) = (2, 6)
The midpoint is going to have an x and y value halfway between those of the two endpoints. The midpoint has an x value 6 higher than the first endpoint and a y value 4 lower. Just continue this pattern to get the other endpoint. (-2+6, 6-4)=(4, 2) The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2] By substituting the given values into the formula we have: (x1 + -8)/2 = -2 and (y1 + 10)/2 = 6 x1 - 8 = -4 and y1 + 10 = 12 x1 -8 + 8 = -4 + 8 and y1 + 10 - 10 = 12 - 10 x1 = 4 and y1 = 2 Thus, the other endpoint is (4, 2).
If R = (xr, yr) and P = (xp, yp) then the midpoint is [(xr + xp)/2, (yr + yp)/2].
Midpoint of (3, -6) and (-5, 2) = [(3-5)/2, (-6+2)/2] = (-1, -2)
The midpoint between -2 and 6 is 2. 2 is 4 units away from both 6 and -2.
If you mean points of (-3, -2) and (6, 2) then the midpoint is at (1.5, -3)
If you mean: (2, 2) and (8, -6) Then midpoint: (2+8)/2 and (2-6)/2 which is (4, -2)
If you mean points of (-4, 6) and (4, -2) then the midpoint is at (0, 2)
Points: (-4, 6) and (4, -2) Midpoint: (0, 2)
Endpoints: (-2,-2) and (4, 6) Midpoint: (1, 2)
If you mean points of (-4, 6) and (4, -2) then the midpoint is at (0, 2)
If you mean points of (-4, 6) and (4, -2) then the midpoint is at (0, 2)
Midpoint = (6+16)/2 and (6-6)/2 = (11, 0)
The midpoint is at (3, 4)
If you mean points of (-2, 4) and (6, -4) then the midpoint is at (2, 0)
It is: (-4+2)/2 and (-2+6)/2 = (-1, 2) which is the midpoint of the line segment.