Points: (-1, -9) and (4, -2) Midpoint: (3/2, -11/2)
Midpoint of (3, -6) and (-5, 2) = [(3-5)/2, (-6+2)/2] = (-1, -2)
(1,1). The midpoint between 6 & -4 is 1, and the midpoint between -2 and 4 is 1. The equation for this line is y = -0.6*x + 1.6, by the way. Check that (1,1) lies on the line.
It is the midpoint of the class interval. I.e let b=the highest number in the class, a = the lowest number in the class. The midpoint is (a+ 1/2(b-a)).
If R = (xr, yr) and P = (xp, yp) then the midpoint is [(xr + xp)/2, (yr + yp)/2].
Points: (-1, -9) and (4, -2) Midpoint: (3/2, -11/2)
If the endpoints are: (3, 7) and (2, -1) then the midpoint is at (2.5, 3)
Endpoints: (-2,-2) and (4, 6) Midpoint: (1, 2)
Points: (-1, 5) and (-6, -2) Midpoint: (-3.5, 1.5)
Points: (-1, 5) and (-6, -2)Midpoint: (-3.5, 1.5)
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If you mean points of (-2, -2) and (4, 6) then the midpoint is at (1, 2)
Endpoints: (-2,-2) and (4, 6) Midpoint: (1, 2)
Points: (-2, -4) and (4, -14) Midpoint: (1, -9)
-1 ie (-3 + 2) and (1 - 2)
If you mean points of (-2, -2) and (4, 6) then the midpoint is at (1, 2)