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Where is 3 fourths on a ruler located?
In an inch, there are 16 lines. It should be the 12th line. From line 0 to line 12 is 3/4 an inch.
What is the perpendicular bisector equation of the line joined by the points of -1 3 and -2 -5?
Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y--1 = -1/8(x--3/2) => y = -1/8x-19/16
What is the slope of a line parallel to 1.6x-3.2y equals 16?
1.6x - 3.2y = 16 3.2y = 1.6x - 16 y = 0.5x - 5 So slope = coefficient of x = 0.5
Given that the points 16 -5 and -40 16 lie on a line what is the equation of the line?
The gradient m between two points (x0, y0) and (x1, y1) is given by m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0) Equation of a line through a point (x0, y0) with gradient m is given by: y - y0 = m(x - x0) Thus for the points (16, -5) and (-40, 16): m = (16 - -5) / (-40 - 16) = 21/-56 = -3/8 y - -5 = -3/8(x - 16) → 8y + 40 = -3x +48 → 8y + 3x = 8
What is the median of 16 94 66 29 and 40?
If you line up 94 66 40 29 16 like I just did you will see the 40 is in the
What is the midpoint of the line segment with endpoints 16 5 and -6 -9?
If you mean endpoints of (16, 5) and (-6, -9) then its midpoint is (5, -2)
What is the perpendicular bisector equation of the line segment whose endpoints are at -1 3 and -2 -5?
Endpoints: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y --1 = -1/8--3/2 => y = -1/8x -19/16
Is line segment AB the same as line segment BA?
Yes, while naming a line segment, as long as the two points are on the line, it does not matter what order they are in or which points they are. well their not
What is the class midpoint?
midpoint between 4-16
1The length of the major axis of the ellipse below is 16 and the length of the red line segment is 8 How long is the blue line segment?
8
The class midpoint is?
midpoint between 4-16
Gr equals 16 Br equals 8 and B is between G and R Is B the midpoint of segment Gr?
Yes, because GB = GR - RB
What is the perpendicular bisector equation of the line whose end points are at 3 5 and 7 7 on the Cartesian plane?
Endpoints: (3, 5) and (7,7) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Perpendicular bisector equation: y-6 = -2(x-5) => y = -2x+16
How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
Point b is the midpoint of the line segment pq line segment pq is eight centimeters longer than line segment pb what is the number of centimeters in the length of line segment qb?
Because b is the mid point of pq, pb = qb. pb is half as long as pq Eq#1....pb = 1/2 pq Eq#2....pq = pb +8 Substitute Eq#1 into Eq #2 pq = 1/2 pq + 8 subtracting1/2 pq from both sides 1/2 pq = 8 pq = 16 problem here: you can't subtract 1/2 ... you would have to divide.
What is the perpendicular bisector equation meeting the line segment of 3 5 and 7 7?
Line segment: (3, 5) and (7, 7) Midpoint: (3+7)/2, (5+7)/2 = (5, 6) Slope or gradient: (7-5)/(7-3) = 1/2 Perpendicular slope = -2 Equation: y -6 = -2(x-5) => y = -2x+10+6 => y = -2x+16 So the perpendicular bisector equation is y = -2x+16
What is the midpoint between 6 6 and 16 -6?
Midpoint = (6+16)/2 and (6-6)/2 = (11, 0)
