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Q: What is the midpoint of the line segment with endpoints (1-6) and (3-4)?

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In an inch, there are 16 lines. It should be the 12th line. From line 0 to line 12 is 3/4 an inch.

Points: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y--1 = -1/8(x--3/2) => y = -1/8x-19/16

1.6x - 3.2y = 16 3.2y = 1.6x - 16 y = 0.5x - 5 So slope = coefficient of x = 0.5

with regard to question 16 above could any part of the speed line ever become perfectly vertical

The gradient m between two points (x0, y0) and (x1, y1) is given by m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0) Equation of a line through a point (x0, y0) with gradient m is given by: y - y0 = m(x - x0) Thus for the points (16, -5) and (-40, 16): m = (16 - -5) / (-40 - 16) = 21/-56 = -3/8 y - -5 = -3/8(x - 16) → 8y + 40 = -3x +48 → 8y + 3x = 8

Related questions

If you mean endpoints of (16, 5) and (-6, -9) then its midpoint is (5, -2)

Endpoints: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y --1 = -1/8--3/2 => y = -1/8x -19/16

Yes, while naming a line segment, as long as the two points are on the line, it does not matter what order they are in or which points they are. well their not

midpoint between 4-16

midpoint between 4-16

8

Yes, because GB = GR - RB

Midpoint = (6+16)/2 and (6-6)/2 = (11, 0)

Endpoints: (3, 5) and (7,7) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Perpendicular bisector equation: y-6 = -2(x-5) => y = -2x+16

17.5

Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16

Because b is the mid point of pq, pb = qb. pb is half as long as pq Eq#1....pb = 1/2 pq Eq#2....pq = pb +8 Substitute Eq#1 into Eq #2 pq = 1/2 pq + 8 subtracting1/2 pq from both sides 1/2 pq = 8 pq = 16 problem here: you can't subtract 1/2 ... you would have to divide.

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