3 = 3^(1)
9 = 3(2)
??? = 3^(3)
81 = 3^(4)
243 = 3^(5)
729 = 3^(6)
There are TWO missing numbers !!! They are 3^(3) = 27 & 3^(0) = 1
1 = 3^(0)
3 = 3^(1)
9 = 3(2)
27 = 3^(3)
81 = 3^(4)
243 = 3^(5)
729 = 3^(6)
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No. 729/3=243; 729/9=81
you divide by three each time 729\3=243\3=81\3=27
729 is the next number in the sequence. You times each number by the past number times by three e.g. 3x3=9, 9x3=27, 27x3= 243, 243x3=729
3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049
9 3 1