3 = 3^(1)
9 = 3(2)
??? = 3^(3)
81 = 3^(4)
243 = 3^(5)
729 = 3^(6)
There are TWO missing numbers !!! They are 3^(3) = 27 & 3^(0) = 1
1 = 3^(0)
3 = 3^(1)
9 = 3(2)
27 = 3^(3)
81 = 3^(4)
243 = 3^(5)
729 = 3^(6)
No. 729/3=243; 729/9=81
you divide by three each time 729\3=243\3=81\3=27
729 is the next number in the sequence. You times each number by the past number times by three e.g. 3x3=9, 9x3=27, 27x3= 243, 243x3=729
3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049
9 3 1
No. 729/3=243; 729/9=81
1, 3, 9, 27, 81, 243, 729
All of these: 1, 3, 9, 27, 81, 243, 729.
Each number is 3 times the previous number, so the next two numbers are 243 and 729: 3 x 81 = 243 3 x 243 = 729
Composite; its factors are 1, 3, 9, 27, 81, 243, 729
1, 3, 9, 27, 81, 243, 729 | 1 x 729, 3 x 243, 9 x 81, 27 x 27.
you divide by three each time 729\3=243\3=81\3=27
729 is divisible by 1, 3, 9, 27, 81, 243, 729.
The factors of 729 are: 1 3 9 27 81 243 729
The factors of 729 are: 1 3 9 27 81 243 729
1, 3, 9, 27, 81, 243, 729.
1, 3, 9, 27, 81, 243, 729: (1 x 729, 3 x 243, 9 x 81, 27 x 27)