The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.
It would be the negative of the negative reciprocal. And since the negative of a negative is a posivie, it is the positive reciprocal.. For example, if the slope was -3, the other would be 1/3.
For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex). Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)
No, parallel lines have exactly same slope Perpendicular line have a slope that is negative reciprocal of each other that is if m = slope of line then slope of perpendicular line is -1/m
A perpendicular lines slope is always the negative or opposite reciprocal of a lines slope. Therefore, if your slope is -13/1 then the perpendicularity of the other line is 1/13. The 13 would change positive there fore its its already a negative number then change it posiive.
The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.
It would be the negative of the negative reciprocal. And since the negative of a negative is a posivie, it is the positive reciprocal.. For example, if the slope was -3, the other would be 1/3.
Yes.
Line a with a slope perpendicular to that of line b has a slope that is the negative reciprocal of line b's. So basically the negative reciprocal.
The negative reciprocal of the slope of the line to which it is perpendicular.
Perpendicular lines have a negative reciprocal slope. Slope of y=2x+5 is 2/1 negative reciprocal is (-1/2)
For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex). Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)
one slope is the negative reciprocal of the other
The slope of the perpendicular to a line has a slope which is the negative reciprocal of the original line's slope.The negative reciprocal of x is -1/xSo in this case, where the slope is -2 the perpendicular line has the slope -1/(-2) or simply 1/2
Slope of perpendicular line is the negative reciprocal. So it is -1/4
They are the negative reciprocal of each other. Fo rexample, if a line has slope = +2, then the line perpendicular to it has slope -1/2
Negative reciprocal is something you use in math that often times help you find a perpendicular line to an equation. ex: for an equation with a slope of 5x, the recriprocal would be -1/5x. what you do is you flip flop the bottom and the top, 1/5x. That is the reciprocal alone and to make it a negative reciprocal you just simply add the negative sign.