The negative reciprocal of any gradient gives the gradient of the line perpendicular to it.
If you had a line of gradient 2, the negative reciprocal would be -1/2
Just change the sign on the number and flip the number/fraction to get the negative reciprocal.
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The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.
It would be the negative of the negative reciprocal. And since the negative of a negative is a posivie, it is the positive reciprocal.. For example, if the slope was -3, the other would be 1/3.
For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex). Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)
No, parallel lines have exactly same slope Perpendicular line have a slope that is negative reciprocal of each other that is if m = slope of line then slope of perpendicular line is -1/m
A perpendicular lines slope is always the negative or opposite reciprocal of a lines slope. Therefore, if your slope is -13/1 then the perpendicularity of the other line is 1/13. The 13 would change positive there fore its its already a negative number then change it posiive.